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Dmitry_Shevchenko [17]
3 years ago
9

. Calculate the unbalanced force acting on a 0.50 kg toy rocket that accelerates at a constant rate with a velocity of 20 m/s (u

p) to 45 m/s (up) in 0.7 s.
Physics
1 answer:
Kruka [31]3 years ago
8 0

Answer:

17.85N

Explanation:

Given data

m= 0.5kg

u= 20m/s

v= 45m/s

t= 0.7second

From

F= mΔv/t

substitute

F=0.5*(45-20)/0.7

F=0.5*25/0.7

F=12.5/0.7

F=17.85

Hence the force is 17.85N

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Answer:

14.79 kgm/s

Explanation:

Data provided in the question

Let us assume the mass of baseball =  m = 0.145 kg

The Initial velocity of pitched ball = v_i = 47 m/s

Final velocity of batted ball in the opposite direction = v_f= -55m/s

Based on the above information, the change in momentum is

\Delta P = m(v_f -v_i)

=  0.145 kg(-55m/s - 47m/s)    

= 14.79 kgm/s

Hence, the magnitude of the change in momentum of the ball is 14.79 kg m/s

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added to the engine minus the waste heat

Explanation:

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Thermodynamics is used to measure the energy changes that accompanies physical and chemical process.

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  Internal energy = Quantity of heat added - Work done on it

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