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Dmitry_Shevchenko [17]
3 years ago
9

. Calculate the unbalanced force acting on a 0.50 kg toy rocket that accelerates at a constant rate with a velocity of 20 m/s (u

p) to 45 m/s (up) in 0.7 s.
Physics
1 answer:
Kruka [31]3 years ago
8 0

Answer:

17.85N

Explanation:

Given data

m= 0.5kg

u= 20m/s

v= 45m/s

t= 0.7second

From

F= mΔv/t

substitute

F=0.5*(45-20)/0.7

F=0.5*25/0.7

F=12.5/0.7

F=17.85

Hence the force is 17.85N

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Vector A has magnitude 13.0 m and vector B has magnitude 16.0 m. The scalar product A.B is 116 m2. What is the magnitude of the
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Answer:

\text{Vector product}=172.66\ m^2

Explanation:

Given that,

The magnitude of vector A, |A|=13\ m

The magnitude of vector B, |B|=16\ m

Scalar product of A and B, A{\cdot} B=116\ m^2

The formula for the scalar product is given by :

A{\cdot} B=|A||B|\cos\theta

Where, \theta is the angle between A and B.

\cos\theta=\dfrac{116}{13\times 16}\\\\\theta=\cos^{-1}\left(0.5576\right)\\\\\theta=56.11^{\circ}

The formula for the vector product is given by :

A\times B=|A||B|\sin\theta\\\\=13\times 16\times \sin56.11\\\\=172.66\ m^2

So, the vector product between these two vectors is 172.66\ m^2.

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3 years ago
A college student likes to take her books to class by placing them in a box and pulling the box around behind her. She pulls on
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Hope this helps!!

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8 0
3 years ago
The magnitude of a uniform electric field between two plates is about 1.7 × 106N/C. If the distance
ASHA 777 [7]

Answer:

V = E*d

D = 1.5 cm * [1 m / 100 cm] = 0.015m

V = 2.9^10^6 N/C * 0.015 m

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The units don't agree in any simple way, but the formula is correct, and it does work.

Explanation:

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All BUT one factor will increase the work output of a machine and decrease the amount of thermal energy created and released. Th
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4 years ago
Read 2 more answers
One end of a metal rod is in contact with a thermal reservoir at 745. K, and the other end is in contact with a thermal reservoi
Masteriza [31]

Answer:

a)S_1=-9.65}\ J/K

b)S_2=71.18\ J/K

c) 0 J/K

d)S= 61.53 J/K

Explanation:

Given that

T₁ = 745 K

T₂ = 101 K

Q= 7190 J

a)

The entropy change of reservoir 745 K

S_1=-\dfrac{7190}{745}\ J/K

Negative sign because heat is leaving.

S_1=-9.65}\ J/K

b)

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S_2=\dfrac{7190}{101}\ J/K

S_2=71.18\ J/K

c)

The entropy change of the rod will be zero.

d)

The entropy change of the system

S= S₁ + S₂

S = 71.18 - 9.65 J/K

S= 61.53 J/K

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4 years ago
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