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DanielleElmas [232]
3 years ago
9

Factor this polynomial 8a^2+2a-6

Mathematics
1 answer:
Naddik [55]3 years ago
7 0
2(4a^2 +a +3)
Factor out the 2 
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Select the most precise name of quadrilateral MNOP given the coordinates of M, N, O, and P.
Harman [31]

Answer:

Square

Step-by-step explanation:

It has four coordinates which means four vertices which is four sides. Can also be a rectangle or parallelogram.

.

3 0
3 years ago
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Please I will rate you with 5 stars just please help me with this problem
olchik [2.2K]

Answer:

D

Step-by-step explanation:

If we isolate the variable in each given compound inequality, we can quickly realize that D is correct.

16\geq 3x+4>1\\12\geq 3x>-3\\4\geq x>-1

x is less than or equal to four (solid point on 4 with line going left), but greater than -1 (open point going right).

Signs with 'or equal to' have solid points, and signs without are not solid.

I hope this helps!

8 0
3 years ago
Answer in yd! need help asap
sweet [91]

Answer:

8 yd

Step-by-step explanation:

The opposite side is 14 and the lower portion plus the missing value would equal 14:

14 = 6 + ?

So subtract 6 from 14 to get the missing length, 8.

8 0
3 years ago
Write an inequality for the given graph.
Aliun [14]
Y=MX+B

M = slope

B = y intercept (number that intersects with the line in the y axis)

y=-3/4x+2

It starts on the y intercept (2) then we travel to the next point (4 on the x axis)

So we travel 3 spaces down (-3) landing on the origin (0,0) then four spaces to the right (4). Getting the slope of -3/4 (rise over run)

Then just plug in these into the equation

y = -3/4 + 2
5 0
3 years ago
Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.
WINSTONCH [101]

Answer:

a) y(t) = y_{0}e^{4t} + 2. It does not have a steady state

b) y(t) = y_{0}e^{-4t} + 2. It has a steady state.

Step-by-step explanation:

a) y' -4y = -8

The first step is finding y_{n}(t). So:

y' - 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r - 4 = 0

r = 4

So:

y_{n}(t) = y_{0}e^{4t}

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' -4(y_{p}) = -8

(C)' - 4C = -8

C is a constant, so (C)' = 0.

-4C = -8

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{4t} + 2

b) y' +4y = 8

The first step is finding y_{n}(t). So:

y' + 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r + 4 =

r = -4

So:

y_{n}(t) = y_{0}e^{-4t}

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' +4(y_{p}) = 8

(C)' + 4C = 8

C is a constant, so (C)' = 0.

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{-4t} + 2

6 0
3 years ago
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