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3 years ago

15

John can paint a house in 10 hours. Adam can paint the same house in 15 hours. Write an equation that can be used to find the ti

me in hours, t, it would take John and Adam to paint to house together.

1 answer:

LenaWriter [7]3 years ago

3 0

10+15=t That’s the equation you need to use

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34 is what percent of 80? (Round to the nearest whole number)

Marizza181 [45]

Answer:

42.5

34:80*100 =

(34*100):80 =

3400:80 = 42.5

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Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .

$\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2$ .

$\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2$ .

Solve this equation for $u$ :

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$u^{2} = 1$ .

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Given that $0 \le x < 2\pi$ ,

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$k = 0$ or $k = 1$ . Accordingly,

$x = 0$ or $x = \pi$ .

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Please solve <br><br> ??+1/16=3/2

Vladimir79 [104]

Answer:

x = 23/16

Step-by-step explanation:

x + 1/16 = 3/2

Get a common denominator

x + 1/16 = 3/2 *8/8

x + 1/16 = 24/16

Subtract 1/16 from each side

x+1/16 -1/16 = 24/16 -1/16

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Multiply your total by your percentage

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The side lengths are the same.
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