Answer:
The answer would be G.
Step-by-step explanation.
To get your answer, you have to pick two points. Ex: (0,4) (4,1)
Put them into the slop equation: slope= y2-y1/x2-x1
slope:1-4/4-0= -3/4
Answer:
.
Step-by-step explanation:
The given function is

Using chain rule differentiate w.r.t. x.
![\left[\because \dfrac{d}{dx}\sin x=\cos x\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Csin%20x%3D%5Ccos%20x%5Cright%5D)
![f'(x)=\cos(9\ln (x))\left[9\dfrac{d}{dx}(\ln (x))\right]](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Ccos%289%5Cln%20%28x%29%29%5Cleft%5B9%5Cdfrac%7Bd%7D%7Bdx%7D%28%5Cln%20%28x%29%29%5Cright%5D)
![\left[\because \dfrac{d}{dx}\ln x=\dfrac{1}{x}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Cln%20x%3D%5Cdfrac%7B1%7D%7Bx%7D%5Cright%5D)

Therefore,
.
· Perpendicular lines have slopes that are opposite reciprocals of each other
· Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept
If the slope of the first line is 3, the slope of the second line is -1/3. Since the lines intersect at the origin, neither of them have a y-intercept.
Answer:
C) y = -1/3x
The situation can be modeled with the linear equation:
$75 + y*($75/x) = $100
<h3>
Which of the following equations represents this situation? </h3>
We know that if she wors for x hours, she earns $75.
This means that the amount that she gets per hour is:
R = $75/x.
Now, if she works y more hours, then she gets another $25 (for a total of $100).
We can write this as a linear equation:
y*($75/x) = $25
We can rewrite this as:
$75 + y*($75/x) = $100
So the correct option is B.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
Answer:
(1)

(2)
Step-by-step explanation:
we are given


we have to find (f+g)(x)
we can write

now, we can plug values
and we get

we can also write as

so, answer is
