The length of a rectangular garden is 3yd more than twice it’s width. The perimeter of the garden is 36yd. What are the width an
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Answer:
a)
b)
Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.
c)
d)
e) Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70
f) Figura attached.
g) When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.
By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.
Step-by-step explanation:
For this case w ehave the following dataset given:
13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70.
Part a
The mean is calculated with the following formula:
The median on this case since we have 27 observations and that represent an even number would be the 14 position in the dataset ordered and we got:
Part b
The mode is the most repeated value on the dataset on this case would be:
Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.
Part c
The midrange is defined as:
And if we replace we got:
Part d
For the first quartile we need to work with the first 14 observations
13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25
And the Q1 would be the average between the position 7 and 8 from these values, and we got:
And for the third quartile Q3 we need to use the last 14 observations:
25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70
And the Q3 would be the average between the position 7 and 8 from these values, and we got:
Part e
The five number summary for this case are:
Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70
Part f
For this case we can use the following R code:
> x<-c(13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70)
> boxplot(x,main="boxplot for the Data")
And the result is on the figure attached. We see that the dsitribution seems to be assymetric. Right skewed with the Median<Mean
Part g
When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.
By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.
The roof will be in the shape of an isosceles triangle with a base length of 30 m and two sides that are 17 m. The two 17 m beams will have the same angle of elevation since they have to might in the middle.
So to find the angle of elevation, we can split the roof in half vertically to create a right triangle. The base will now be 15 m, and the hypotenuse will be 17. Now we can use a trigonometry function to solve for the angle. We know the hypotenuse and the side adjacent to the angle, so we can use cosine.
The answer is 28.1 degrees
So to find the angle of elevation, we can split the roof in half vertically to create a right triangle. The base will now be 15 m, and the hypotenuse will be 17. Now we can use a trigonometry function to solve for the angle. We know the hypotenuse and the side adjacent to the angle, so we can use cosine.
The answer is 28.1 degrees