For this, we will be using the quadratic formula, which is
, with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this: 
Firstly, solve the multiplications and the exponents: 
Next, do the addition: 
Next, your equation will be split into two:
. Solve them separately, and your answer will be
Answer:
is a function that reverse another function if de function apply to an input x gives a result of a y den applying its inverse function g to y gives de result of x nd opposite eg f (x )=y nd if g (y )=x
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
Answer:
[y]
-16
-12
0
12
16
Step-by-step explanation:
Put the x value in the equation to find your answer
Answer:
Step-by-step explanation:
multiply all number on one
multiply all number on two
multiply all number on three