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siniylev [52]
2 years ago
6

The mixed number 1 2/5 and the decimal number 1.4 can be used to represent the same value.

Mathematics
2 answers:
Inessa05 [86]2 years ago
8 0
True
1 2/5 =1.4
2 divided by 5 is .4
plus the 1
1.4 = 1.4
ivanzaharov [21]2 years ago
7 0

Answer:

False

Step-by-step explanation:

You might be interested in
Square root of50 is it rational true or false
morpeh [17]
Rational numbers end
irrational numbers do not
pi is an irrational number
√2 is an irrational number
so
√50=√2 times √25=√2 times 5
irrational times rational =irrational
√2=irrational

answer is false, it is rrational





3 0
3 years ago
What is the area of this parallelogram?<br><br><br> 104 m²<br><br> 88 m²<br><br> 56 m²<br><br> 32 m²
iragen [17]

Answer: To find area of a rectangle, multiply its base (length) by its height (width). Plug in the base, 7 meters, and the height, 8 meters. So the area of Rectangle DFBE is 56 square meters.

88m

HOPE THIS HELPS

6 0
3 years ago
Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0
andreev551 [17]

Recall the angle sum identity for cosine:

cos(<em>x</em> + <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) - sin(<em>x</em>) sin(<em>y</em>)

cos(<em>x</em> - <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) + sin(<em>x</em>) sin(<em>y</em>)

==>   sin(<em>x</em>) sin(<em>y</em>) = 1/2 (cos(<em>x</em> - <em>y</em>) - cos(<em>x</em> + <em>y</em>))

Then rewrite the equation as

sin(4<em>x</em>) sin(5<em>x</em>) + sin(4<em>x</em>) sin(3<em>x</em>) - sin(2<em>x</em>) sin(<em>x</em>) = 0

1/2 (cos(-<em>x</em>) - cos(9<em>x</em>)) + 1/2 (cos(<em>x</em>) - cos(7<em>x</em>)) - 1/2 (cos(<em>x</em>) - cos(3<em>x</em>)) = 0

1/2 (cos(9<em>x</em>) - cos(<em>x</em>)) + 1/2 (cos(7<em>x</em>) - cos(3<em>x</em>)) = 0

sin(5<em>x</em>) sin(-4<em>x</em>) + sin(5<em>x</em>) sin(-2<em>x</em>) = 0

-sin(5<em>x</em>) (sin(4<em>x</em>) + sin(2<em>x</em>)) = 0

sin(5<em>x</em>) (sin(4<em>x</em>) + sin(2<em>x</em>)) = 0

Recall the double angle identity for sine:

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

Rewrite the equation again as

sin(5<em>x</em>) (2 sin(2<em>x</em>) cos(2<em>x</em>) + sin(2<em>x</em>)) = 0

sin(5<em>x</em>) sin(2<em>x</em>) (2 cos(2<em>x</em>) + 1) = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   2 cos(2<em>x</em>) + 1 = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   cos(2<em>x</em>) = -1/2

sin(5<em>x</em>) = 0   ==>   5<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   5<em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>

… … … … …   ==>   5<em>x</em> = 2<em>nπ</em>   <u>or</u>   5<em>x</em> = (2<em>n</em> + 1)<em>π</em>

… … … … …   ==>   <em>x</em> = 2<em>nπ</em>/5   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>/5

sin(2<em>x</em>) = 0   ==>   2<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>

… … … … …   ==>   2<em>x</em> = 2<em>nπ</em>   <u>or</u>   2<em>x</em> = (2<em>n</em> + 1)<em>π</em>

… … … … …   ==>   <em>x</em> = <em>nπ</em>   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>/2

cos(2<em>x</em>) = -1/2   ==>   2<em>x</em> = arccos(-1/2) + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = -arccos(-1/2) + 2<em>nπ</em>

… … … … … …    ==>   2<em>x</em> = 2<em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = -2<em>π</em>/3 + 2<em>nπ</em>

… … … … … …    ==>   <em>x</em> = <em>π</em>/3 + <em>nπ</em>   <u>or</u>   <em>x</em> = -<em>π</em>/3 + <em>nπ</em>

<em />

(where <em>n</em> is any integer)

5 0
2 years ago
A telemarketing firm is monitoring the performance of its employees based on the number of sales per hour. One employee had the
Len [333]

Answer:

First quartile = 3.5

Third quartile = 6.5

Step-by-step explanation:

Sales for last 20 hours :

3, 4, 5, 5, 6, 7

Using the data given :

The first quartile, Q1 ;

Q1 = 1/4(n+1)th term

n = 6

Q1 = 1/4(6 + 1)th term

Q1 = 7/4 = 1.75 th term

(3 + 4) / 2 = 7/2 = 3.5

The third quartile, Q3:

Q3 = 3/4(n+1)th term

n = 6

Q3 = 3/4(6 + 1)th term

Q3 = 21/4 = 5.25th term

(5th + 6th) term / 2

(6 + 7) / 2 = 13/2 = 6.5

6 0
3 years ago
If you are given a part-to-whole ratio, can you write part-to-part ratio? Explain
stealth61 [152]

There are 2 types of ratios: Part-to-Wholes, and Part-to-Part ratios.

Part-to-part ratios show the relationship between the two groups.

Lets say theres 10 fruits in a fruit bowl.

If you have 3 apples, and 7 oranges, then the ratio is 3:7 as the part-to-part ratio. But the part-to-whole ratio would be either 3:10 ( for apples) or 7:10 (for oranges)

8 0
3 years ago
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