Q + n = 40....q = 40 - n
0.25q + 0.05n = 5
0.25(40 - n) + 0.05n = 5
10 - 0.25n + 0.05n = 5
-0.25n + 0.05n = 5 - 10
- 0.20n = -5
n = -5 / -0.20
n = 25 <=== 25 nickels
q + n = 40
q + 25 = 40
q = 40 - 25
q = 15 <== 15 quarters
Answer:
b
Step-by-step explanation:
83+37=129, 120÷24=5
Answer:
Midpoint of side EF would be (-.5,4.5)
Step-by-step explanation:
We know that the coordinates of a mid-point C(e,f) of a line segment AB with vertices A(a,b) and B(c,d) is given by:
e=a+c/2,f=b+d/2
Here we have to find the mid-point of side EF.
E(-2,3) i.e. (a,b)=(2,3)
and F(1,6) i.e. (c,d)=(1,6)
Hence, the coordinate of midpoint of EF is:
e=-2+1/2, f=3+6/2
e=-1/2, f=9/2
e=.5, f=4.5
SO, the mid-point would be (-0.5,4.5)
Answer:
c=10
Step-by-step explanation:
The solution to the first expression - 7+3(9-4)^2÷5 is given as 22.
To get the answer correctly, one must follow rudimentary rules of operations which are coined into the acronym BODMAS.
<h3>What is BODMAS?</h3>
This is the order in which mathematical operations must be executed.
B = Bracket
O = Orders (that is Powers, Indices or roots)
D= Division
M = Multiplication
A = Addition
S = Subtraction
Now lets see how we got 22 from the first set of operations:
<h3>Operation 1 (Example)</h3>
7+3(9-4)^2÷5 =
7+3 (5)^2÷5=
7+3 * 25÷5 =
7+3*5=
7+15=
22
Following the BODMAS rule and the example in Operation 1 above, we can state the remaining answers as follows:
<h3>
Operation 2</h3>
12/3-4+7^2 = 49
<h3 /><h3>
Operation 3</h3>
(7-3)×3^3÷9 = 12
<h3>Operation 4</h3>
5(7-3)^2÷(6-4)^3-9 = 1
<h3>Operation 5</h3>
3×(7-5)^3÷(8÷4)^2-5 = 1
<h3>Operation 6</h3>
9+(3×10)/5×2-12 = 9
See the link below for more about Mathematical Operations:
brainly.com/question/14133018
