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2 years ago

6

The pulley system has a mechanical advantage of 5. Determine how much input force is required to achieve 1000 N of lifting force

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1 answer:

Katen [24]2 years ago

8 0

I don’t think I need anything from my dad to get my hair fixed so I’m just bored I don’t want you guys

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A 400 µF capacitor is constructed out of two parallel plates of very large area which are separated by 1 mm. A battery is used t

Kay [80]

Answer:

W=2 J

Explanation:

Given that

C= 400 µF

V= 100 V

d= 1 mm

Energy before disconnected from the battery

U= 1/2 CV²=Q²/(2C)

Energy after disconnected from the battery

U'=1/2 C'V²=Q²/(2C')

The work done W

W= U' - U

W= Q²/(2C') - Q²/(2C)

$W=\dfrac{Q^2}{2C}\left ( \dfrac{C}{C'} -1\right )$

1/2 CV²=Q²/(2C)

$W=\dfrac{CV^2}{2}\left ( \dfrac{C}{C'} -\right )$

We know that

$C=\dfrac{\varepsilon _oA}{d}$

$C'=\dfrac{\varepsilon _oA}{d'}$

Given that

d'=2mm ,d= 1mm

C/C'= d'/d= 2

$W=\dfrac{CV^2}{2}\left ( \dfrac{C}{C'} -\right )$

By putting the values

$W=\dfrac{400\times 10^{-6}\times 100^2}{2}( 2 -1 )$

W=2 J

6 0

2 years ago

A concave mirror of focal length 10cm forms an inverted image of 40cm from the mirror and 4cm high. Determine the position and s

Alika [10]

The equation of the constructor of the geomeric optics allows to find the results for the distance and size of the objects are:

Distance from the mirror to the object is: p = 13.3 cm

The height of the object is: h = 1.33 cm

The equation of the constructor of geometric optics describes the position of objects and their images for mirrors and lenses.

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

Where f is the focal length, p and q are the distances to the object and the image, respectively.

They indicate the focal length f = 10 cm, the distance to the image q = 40 cm, that the height s h ’= 4 cm. In the attachment we see a scheme of the system.

Let's find the distance to the object.

$\frac{1}{p\frac{x}{y} } = \frac{1}{f} - \frac{1}{q} \\\frac{1}{p} = \frac{1}{10} - \frac{1}{40}\\\frac{1}{p} = 0.075$

p = 13.3 cm

The magnification in the ratio of image size to object size. The image is inverted so its height is negative.

$m = \frac{h'}{h} = - \frac{q}{p}\\h = - \frac{p}{q} \ h'\\h = - \frac{13.3}{40}\ (-4)$

h = 1.33 cm

In conclusion using the equation of the constructor we can find the results for the distance and size of the objects are:

Distance from the mirror to the object is 13.3 cm

The height of the object is 1.33 cm

Learn more here: brainly.com/question/14314471

7 0

2 years ago

A circus performer stretches a tightrope between two towers. He strikes one end of the rope and sends a wave along it toward the

IgorC [24]

Explanation:

The given data is as follows.

Distance (s) = 20 m

time (t) = 0.775 s

Also, it is given that mass per 1 meter length (m) = 0.300 kg

Formula to calculate the velocity is as follows.

Velocity (v) = $\frac{s}{t}$

Putting the given values into the above formula as follows.

v = $\frac{s}{t}$

= $\frac{20 m}{0.775 s}$

= 25.80 m/s

We know that,

v = $\sqrt{\frac{T}{m}}$

Taking square on both the sides, the formula will become as follows.

T = $mv^{2}$

= $0.3 kg \times 25.80$

= 199.692 N

Therefore, we can conclude that tension in the given tightrope is equal to 199.692 N .

5 0

2 years ago

Which type of bond and how many bonds would occur as carbon dioxide.. (CO2) is formed from carbon in Group IVA and oxygen in Gro

Ahat [919]

Answer:

four covalent bonds is the answer

3 0

2 years ago

Eight books, each 4.6 cm thick and of mass 1.8 kg, lie on a flat table. How much work work is required to stack them on top of o

pantera1 [17]

Answer:

529.92Newton Meters

Explanation:

Work=force x displacement

8books in total

force is 1.8kg

dispplacement is 4.6cm

times both units by 8 and u get

force - 14,4

displacement - 36.8

now times boht together and u get 529.92nm

3 0

2 years ago