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2 years ago

6

The pulley system has a mechanical advantage of 5. Determine how much input force is required to achieve 1000 N of lifting force

.

1 answer:

Katen [24]2 years ago

8 0

I don’t think I need anything from my dad to get my hair fixed so I’m just bored I don’t want you guys

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Um objeto sobe verticalmente com velocidade de 10m/s . Quando sua altura é de 60m , uma parte desse objeto cai . Considerando g=

schepotkina [342]

Why is it in Spanish????????????????

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3 years ago

I measured my pet dog (Mickey) to be able to run the length of my backyard 500 in 12 seconds. At this rate, how many miles can m

Georgia [21]

The dog runs 300240 miles.

<h3>What is the rate?</h3>

Rate refers to the pace at which something happens. We know that the easiest way to obtain the rate is by the use of proportion. Now we have been told that the dog is able to run 500 miles in 12 seconds.

If the dog runs 500 miles in 12 seconds

The dog runs x miles in 1 second

x = 500 * 1/12

x = 41.7 miles

In two hours we have 2 * 60 * 60 = 7200 seconds

If the dog runs 41.7 miles in 1 second

The dog runs x miles in 7200 seconds

x = 41.7 miles * 7200 seconds/ 1 second

x = 300240 miles

Learn more about proportion:brainly.com/question/2548537

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2 years ago

Select the correct answer from each drop-down menu.

amid [387]

Answer:

Rust is a compound. What makes iron rust is its reaction with oxygen and moisture in the air.

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3 years ago

A vector always consits of

Kazeer [188]

Answer:

Size and Direction

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3 years ago

(a) What is the ionization energy of a hydrogen atom that is in the n = 6 excited state? (b) For a hydrogen atom, determine the

crimeas [40]

Answer:

(a) 0.3778 eV

(b) Ratio = 0.0278

Explanation:

The Bohr's formula for the calculation of the energy of the electron in nth orbit is:

$E=\frac {-13.6}{n^2}\ eV$

(a) The energy of the electron in n= 6 excited state is:

$E=\frac {-13.6}{6^2}\ eV$

$E=-0.3778\ eV$

Ionisation energy is the amount of this energy required to remove the electron. Thus, |E| = 0.3778 eV

(b) For first orbit energy is:

$E=\frac {-13.6}{1^2}\ eV$

$E=-13.6\ eV$

$Ratio=\frac {E_6}{E_1}$

$Ratio=\frac {-0.3778}{-13.6}$

Ratio = 0.0278

7 0

3 years ago