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3 years ago

Explain in detail what happens to the Earths surface after an earthquake due to the force of tension

1 answer:

8 0

After the two plates Collide the amount of tension is what makes the two plates slip. When two plates slip the Earths surface begins to move because of the slipping of the plates thats when we feel an earth quake. After the earth quake is finshed the tension between the two plates happen again so the Earths surface may be cracked as a result of the immense slipping. But the tension will happen again and devolpe slowly over time. Intill it happens again almost like a cycle

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The vector position of an object is given by r what is the torque acting on the object about the origin when a force f = (−12.5i

attashe74 [19]

Let the vector position of the object in the (x-y) plane be
$\vec{r} = x \hat{i} + y \hat{j}$

The applied force is
$\vec{f} = -12.5 \hat{i}
$

By definition, the applied torque is
$\vec{T} = \vec{r} \times \vec{f} = (x\hat{i} + y\hat{j}) \times (-12.5y \hat{i}) = 12.5\hat{k}$

Answer: $12.5y \, \hat{k}$

7 0

3 years ago

An object has a height of 0.066 m and is held 0.210 m in front of a converging lens with a focal length of 0.140 m. (Include the

Anvisha [2.4K]

Explanation:

Given that,

Size of object, h = 0.066 m

Object distance from the lens, u = 0.210 m (negative)

Focal length of the converging lens, f = 0.14 m

If v is the image distance from the lens, we can find it using lens formula as follows :

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{0.14 }+\dfrac{1}{(-0.21)}\\\\v=0.42\ m$

(a) Magnification,

$m=\dfrac{v}{u}\\\\m=\dfrac{0.42}{(-0.21)}\\\\m=-2$

(b) Magnification, $m=\dfrac{h'}{h}$

h' is image height

$-2=\dfrac{h'}{0.066}\\\\h'=-2\times 0.066\\\\h'=-0.132\ m$

Hence, this is the required solution.

4 0

2 years ago

Compute the density in g/cm^3 of a piece of metal that had mass of 0.485 kg and a volume of 52cm^3

steposvetlana [31]

Answer:

9.3 g/cm³

Explanation:

First, convert kg to g:

0.485 kg × (1000 g / kg) = 485 g

Density is mass divided by volume:

D = (485 g) / (52 cm³)

D = 9.33 g/cm³

Rounding to two significant figures, the density is 9.3 g/cm³.

8 0

2 years ago

How is an image formed by a plane mirror?

Nesterboy [21]

<h3><u>Answer;</u></h3>

Light bounces off of the mirror and then appears to come from behind the mirror.

<h3><u>Explanation;</u></h3>

<u><em>Plane mirrors form images that are virtual, upright and the same size and shape as the object it is reflecting.</em></u>
<em><u>When rays of light from the object hits a plane mirror they bounces off the mirror,that is they undergo reflection, and appear to originate from behind the mirror, resulting to the formation of a virtual image.</u></em>
The image formed appears to be behind the plane in which the mirror lies. A virtual image is an image that is formed at a location from which the rays of light appear to come from. The image can not be formed on a screen.

7 0

2 years ago

A=(v – u)/t<br><br> i. V as subject<br> ii. U as subject<br> iii. T as subject

Norma-Jean [14]

Answer:

$a = \frac{(v - u)}{t} \\ v - u = at \\ v = at + u$