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forsale [732]
3 years ago
7

If cosx+sinx=sqrt(2)cosx then show that cosx-sinx=sqrt(2)sinx

Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0
Hello,

We suppose cos (x)≠0 and sin(x)≠0

cos(x)+sin(x)=√2 cos(x)
==>1+tg(x)=√2
==>tg(x)=√2-1
==>1/tg(x)=1/(√2-1)
==>cos (x)/sin(x)= √2+1
==>cos(x)=sin(x)+√2*sin(x)
==>cos(x)-sin(x)=√2 sin(x)

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Emily is encouraged to read more than 4 hours each week. It takes her 45 minutes to finish her first book. She divides the remai
Dennis_Churaev [7]

Answer:

32 mins 50 seconds

Step-by-step explanation:

Total number of hours to read weekly \geq 4

she has read for 45 minutes, so she has 4 hrs - 45 minutes = 3 hrs 15 minutes left

Dividing the time equally = 195 mins / 6

minimum number of minutes to read \geq 32 minutes 50 seconds

4 0
3 years ago
Sustituir. 20c + 15r + 75p + 50e​
AVprozaik [17]

Answer:

8c - 7r + 10p - 20e

Step-by-step explanation:

Subtract (20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)

(20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)

Open bracket

20c + 15r + 75p + 50e - 12c - 22r - 65p - 70e

Collect like terms

= 20c - 12c + 15r - 22r + 75p - 65p + 50e - 70e

= 8c - 7r + 10p - 20e

3 0
3 years ago
A box contains
Alex787 [66]
I'm not entirely sure but it should be (3/5) together. For pen the probability is (5/20) and for crayon is (12/20) add them equals (12/20) simply equals (3/5) HOPE IT HELPS
4 0
3 years ago
Suppose that birth weights are normally distributed with a mean of 3466 grams and a standard deviation of 546 grams. Babies weig
Anon25 [30]

Answer:

3.84% probability that it has a low birth weight

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3466, \sigma = 546

If we randomly select a baby, what is the probability that it has a low birth weight?

This is the pvalue of Z when X = 2500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2500 - 3466}{546}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384

3.84% probability that it has a low birth weight

3 0
3 years ago
You are making fruit baskets using 54 apples, 36 oranges, and 73 bananas.
matrenka [14]

Step-by-step explanation:

54×36=1,944 1,944÷73=23.63

6 0
3 years ago
Read 2 more answers
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