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Sergeu [11.5K]
3 years ago
11

What is the GCF of 12 and 8

Mathematics
2 answers:
andre [41]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Factor the two given numbers into primes.

12: 2 * 2 * 3

8: 2 * 2 * 2

They both have 2 * 2 in common.

The highest common factor is 4

lina2011 [118]3 years ago
3 0

Answer:

4

Step-by-step explanation:

12 = 4 * 3

8 = 4 * 2

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Julie's MP3 player contains 860 songs. If 20% of the songs are rap songs and 15% of the songs are R&B songs, how many of the
docker41 [41]
Total number of songs in Julie's MP3 player = 860
Percentage of rap songs in Julie's MP3 player = 20%
Then
Number of rap songs in Julie's MP3 player = (20/100) * 860
                                                                     = 860/5
                                                                     = 172
Percentage of R&B songs in Julie's MP3 player = 15%
Then
Number of R&B songs in Julie's MP3 player = (15/100) * 860
                                                                        = 1290/10
                                                                         = 129
So
The number of other types of songs in Julie's MP3 player = 860 - (172 + 129)
                                                                                             = 860 - 301
                                                                                             = 559
So the number of other types of songs in Julie's MP3 player was 559.
5 0
3 years ago
Read 2 more answers
Rewrite the following equation in slope-intercept form. 10x - 5y= -17
lorasvet [3.4K]
Slope-intercept form: y = mx + c

10x - 5y = -17
move 10x to the other side.
- 5y = -10x - 17




6 0
4 years ago
The sum of three consecutive even integers is 36 . find the smallest of them​
bonufazy [111]

Answer:

10

Step-by-step explanation:

You can get the three consecutive integers by using <em>algebraic expressions.</em>

Let's solve.

Let x be the <u>smallest even integer</u>.

Let x+2 be the second even integer.

Let x+4 be the largest even integer.

  • x+x+2+x+4 = 36
  • 3x+6 = 36
  • 3x = 36-6
  • 3x = 30
  • x = \frac{30}{3}
  • x = 10

Therefore, 10 is the smallest even integer.

x+2 = 10+2 = 12

The second even integer is 12.

x+4 = 10+4 = 14

The largest even integer is 14.

Let's check by adding the three even integers.

10+12+14 = 36

36 = 36

<em>It's correct. </em>

7 0
3 years ago
A graduate school plans to increase its enrollment capacity by developing its facilities and the programs it offers. Their enrol
kap26 [50]

Answer:

4.4 years

Step-by-step explanation:

Next time, please share the answer choices.

In this case, the beginning enrollment capacity was 120.  The rate of increase was 3.00, the terminal enrollment cap 3,240.  We let t represent the number of years:

3,240 students = (120 students)(3.00)^t

We need to solve this for t, the number of years required before enrollment will hit 3,240 students.

Solve 3240 = 120(3)^t for t:

Divide both sides by 120, obtaining 27.

Then we have

127 = 3^t

Logarithms are the best tool to use here to find t.  Take the natural log of both sides:

log 127 = t log 3.  Solving for t:  t = (log 127) / (log 3), or t = 2.104 / 0.477 = 4.41

Thus, starting at 120 students, enrollment reached 3,240 students in 4.4 years.

7 0
3 years ago
While organizing her DVD collection, Jessica put 5 DVDs on the first rack, 10 DVDs on the second rack, 20 DVDs on the third rack
aleksandrvk [35]

Answer:

160

Step-by-step explanation:

Number of DVDs put on the first rack = 5

Number of DVDs put on the second rack = 10

If we closely observe, the number of DVDs on the second rack is nothing but number of DVDs on the first rack multiplied by 2.

Number of DVDs put on the third rack = 20

If we closely observe, the number of DVDs on the third rack is nothing but number of DVDs on the second rack multiplied by 2.

Number of DVDs put on the fourth rack = 40

If we closely observe, the number of DVDs on the fourth rack is nothing but number of DVDs on the third rack multiplied by 2.

Number of DVDs put on the fifth rack = 80

If we closely observe, the number of DVDs on the fifth rack is nothing but number of DVDs on the fourth rack multiplied by 2.

Therefore, to find the number of DVDs on the sixth rack as per similar pattern, we need to multiply the number of DVDs on the fifth rack with 2.

Number of DVDs on the sixth rack = 80\times 2 = \bold{160}

4 0
3 years ago
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