The answer to the problem is 12-6x
Whats the question?
Sorry but can't answer if theres no question
Answer:
e
Step-by-step explanation:
The cube on the top, the one with the width of 4 is Cube 1.
The other one is Cube 2.
The length of the cube is 4, the width 2, and the height 5.
We know the length is 4 because we can look at the side, where both measurements 6 ft and 3 ft can be found.
We know that the height is 5 because for Cube 2, the height is 3. The total height is 8, so we subtract 3 from 8. We get our difference of 5.
V = l x w x h
V = (4)(2)(5)
V = (8)(5)
V = 40.
Cube 2 has a length is 6, the width 2, and the height 3.
V = l x w x h
V = (6)(2)(3)
V = (12)(3)
V = 36
We add the volumes of both cubes.
40 + 36 = 76
probs not right but hope it helped :)
Answer:
![1. \quad\dfrac{1}{k^{\frac{2}{3}}}\\\\2. \quad\sqrt[7]{x^5}\\\\3. \quad\dfrac{1}{\sqrt[5]{y^2}}](https://tex.z-dn.net/?f=1.%20%5Cquad%5Cdfrac%7B1%7D%7Bk%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%5C%5C%5C%5C2.%20%5Cquad%5Csqrt%5B7%5D%7Bx%5E5%7D%5C%5C%5C%5C3.%20%5Cquad%5Cdfrac%7B1%7D%7B%5Csqrt%5B5%5D%7By%5E2%7D%7D)
Step-by-step explanation:
The applicable rule is ...
![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
It works both ways, going from radicals to frational exponents and vice versa.
The particular power or root involved can be in either the numerator or the denominator. The transformation applies to the portion of the expression that is the power or root.
Answer:
Help me please in my question
