Answer:
Step-by-step explanation:
Given that the observed frequencies for the outcomes as follows:
To check this we can use chi square goodness of fit test.

(Two tailed test at 5% significance level)
Assuming equally likely expected observations are found out and then chi square is calculated as (0-E)^2/E
Df = 6-1 =5
Outcome	Frequency	Expected frequency	(Obs-exp)^2/Exp
    
1	36	34.83333333	0.03907496
2	30	34.83333333	0.670653907
3	41	34.83333333	1.091706539
4	40	34.83333333	0.766347687
5	23	34.83333333	4.019936204
6	39	34.83333333	0.498405104
    
 209	209          7.086124402
p value =0.214
Since p >alpha, we accept null hypothesis
It appears that the  loaded die does not behave differently than a fair die at 5% level of significance