We shall use the formula for distance traveled:
s = ut + (1/2)at^2
where
u = initial velocity
t = time
a = acceleration.
Because
u = 0 (car starts from rest),
t = 10 s (travel tme),
a = 2 m/s^2 (acceleration), m
the di mstance traveled is
s = (1/2)*(2 m/s^2)*(10 s)^2 = (1/2)*2*100 = 100
Answer: 100 m
Put the dot on the 5 and than go down 4 i think this is right but i might be wrong sorry if i am
The Tenth number percentage
To determine the length of the hypotenuse, we need a relation that would relate the other legs and the hypotenuse of the triangle. So, we would need to use the Pythagorean theorem which is an equation that relates the hypotenuse with the other legs of a right triangle. It is to be noted that this is only usable for right triangles only. It is expressed as follows:
c^2 = a^2 + b^2
where c is the hypotenuse and a, b are the other legs.
c = √(a^2 + b^2)
c = √(6^2 + 8^2)
c = √100
c = 10 m
Therefore, the length of the hypotenuse with the other legs having a length of 6 and 8 would be 10 m.
