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3 years ago

Solve y+1=-3/4 (x+2) and y-3= 2/3 (x-4) please show how you solve it

Mathematics

1 answer:

VashaNatasha [74]3 years ago

7 0

Answer:

y = -3/4x-5/2 and y = 2/3x-1/3

Step-by-step explanation:

y+1 = -3/4(x+2)

y+1 = -3/4x-3/2

y = -3/4x-3/2-1

y = -3/4x-5/2

-----

y-3 = 2/3(x-4)

y-3 = 2/3x-8/3

y = 2/3x-8/3+3

y = 2/3x-1/3

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How many solutions does the equation have?<br> -9 = |d+4|

bezimeni [28]

Answer:

2 solutions

Step-by-step explanation:

Set up a system of equations. The absolute value produces two equations because one answer will be negative and the other positive.

d + 4 = -9

d + 4 = 9

So...

d = -13

d = 5

7 0

3 years ago

I do not remember how to do this please help!

mafiozo [28]

2 / 1 7 -18
2 18
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1 9 0 There is no remainder here. The quotient is x+9

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3 years ago

Read 2 more answers

Consider the following differential equation to be solved by undetermined coefficients. y(4) − 2y''' + y'' = ex + 1 Write the gi

kompoz [17]

Answer:

The general solution is

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2}$

Step-by-step explanation:

Step :1:-

Given differential equation y(4) − 2y''' + y'' = e^x + 1

The differential operator form of the given differential equation

$(D^4 -2D^3+D^2)y = e^x+1$

comparing f(D)y = e^ x+1

The auxiliary equation (A.E) f(m) = 0

$m^4 -2m^3+m^2 = 0$

$m^2(m^2 -2m+1) = 0$

$(m^2 -2m+1) this is the expansion of (a-b)^2$

$m^2 =0 and (m-1)^2 =0$

The roots are m=0,0 and m =1,1

complementary function is $y_{c} = (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x$

<u>Step 2</u>:-

The particular equation is $\frac{1}{f(D)} Q$

P.I = $\frac{1}{D^2(D-1)^2} e^x+1$

P.I = $\frac{1}{D^2(D-1)^2} e^x+\frac{1}{D^2(D-1)^2}e^{0x}$

P.I = $I_{1} +I_{2}$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x + \frac{1}{D^{2} } e^{0x}$

$\frac{1}{D} means integration$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x = \frac{1}{2D} \int\limits {x^2e^x} \, dx$

applying in integration u v formula

$\int\limits {uv} \, dx = u\int\limits {v} \, dx - \int\limits ({u^{l}\int\limits{v} \, dx } )\, dx$

$I_{1}$ = $\frac{1}{D^2(D-1)^2} e^x$

$\frac{1}{2D} (e^x(x^2)-e^x(2x)+e^x(2))$

$\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

$I_{2}$ $= \frac{1}{D^2(D-1)^2}e^{0x}$

$\frac{1}{D} \int\limits {1} \, dx= \frac{1}{D} x$

again integration $\frac{1}{D} x = \frac{x^2}{2!}$

The general solution is $y = y_{C} +y_{P}$

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2!}$

3 0

3 years ago

Weekly math review-Q1.6 what is all the factors of 32

ololo11 [35]

All the factors of 32 include: 1,2,4,8,16,32
Hope this helps! (:

8 0

3 years ago

Alabama has about 2.51 million acres of cropland Florida has about 1.15 times as much cropland as Alabama how much crop land doe

aev [14]

Answer: Florida has 2.8865 million acres of cropland .

Explanation:

Since we have given that

Length of acres of cropland Alabama has = 2.51 millions

According to question, we have Florida has about 1.15 times as much cropland as Alabama has ,

So,

Length of acres of cropland Florida has is given by

$2.51\times 1.15=2.8865\text{ million acres }$

So, Florida has 2.8865 million acres of cropland .

8 0

3 years ago