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kvv77 [185]
3 years ago
6

An online shopping club has 11,200 members when it charges $7 per month for membership. For each $1 monthly

Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

Monthly revenue = R(x) = (11,200 - 400x) * (7 + x)

Step-by-step explanation:

Monthly revenue = Number of members * Monthly fee ......... (1)

Where;

Number of members = 11,200

Monthly fee = $7

For each $1 monthly increase in membership fee, we have

For 1 month, one dollar the decrease = 400 * 1 = 400

For 2 months, 2 dollar increase will lead to decrease of 400* 2 = 800 members

Therefore, for x months

Innrease in membeship fee or price increase = 7 + x

Decrease in the numbers of members = 400x

Substitute the values into equation (1), we have:

Monthly revenue = R(x) = (11,200 - 400x) * (7 + x)

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Mei has 8 jars of soup. Each jar contains 300 milliliters of soup. What is the smallest pot Mei can use to heat all the soup.[PL
Kobotan [32]

Answer: A pot of 2400ml

Step-by-step explanation: Ok, mei has 8 jars, and each jar has 300ml of soup, so the total amount of soup is 8 times 300ml

N = 8*300ml = 2400ml

So the smallest pot that mei can use to heat the soup is a pot that has exactly that volume. 2400ml, (discarding the fact that the volume of the soup will change as it is heated up)

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3 years ago
Help me please and thank you
Scorpion4ik [409]

Answer:

x = 20

y = 10

m∡8 = 110°

Step-by-step explanation:

m∡1 + m∡2 = 180

5x + y + 3x + y = 180

8x + 2y = 180

m∡1 = m∡8    (they are alternate-exterior angles and are congruent)

5x + y = 3x + 5y

2x = 4y

x = 2y

Substitute '2y' for 'x' in 8x + 2y = 180

8(2y) + 2y = 180

18y = 180

y = 10

x = 2(10)

x = 20

m∡8 = 3(20) + 5(10) = 110°

8 0
3 years ago
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kaheart [24]

Answer:

Step-by-step explanation:

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3 years ago
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Marina86 [1]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Invasive species often experience exponential population growth when introduced into a new environment. Zebra mussels are an inv
Oliga [24]

Answer:

If ‘a’ is the initial population of the Zebra mussels, then every six months, the population of Zebra mussels quadruples, i.e. it becomes 4a. In t years, i.e. in 2t intervals of 6 months each, the population of Zebra mussels can be computed with the help of a geometric series a, ar, ar2, ar3, …. arn-1 ( the series being finite with n terms) where a is the 1st term , r is the common ratio and n is the number of terms in the series..

Here, in 2t years, there will be 2t + 1 terms in the geometric series including the initial term. Thus in the above series, a = 10, r = 4 and n = 2t + 1. Then the population of the Zebra mussels after 2t years is the (2t +1)st term of the geometric series I.e. 10* ( 42t)                  

In 15 months, t = 15/12 = 1.25. Then the population of Zebra mussels after 15 months will be 10*(42.5 ) = 10 * 25 = 320

If after t years, the population of the Zebra mussels become 1 million , then we have

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Step-by-step explanation:

8 0
3 years ago
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