“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
Answer:
It’s the third one
Step-by-step explanation:
-1.1x+6.4>-1.3
-1.1x>-1.3-6.4
-1.1x>-7.7 multiplied by -1 gives 1.1x<7.7
Divided by 1.1 you get x<7
Because GH bisects FGI, FGH=HGI
2x+1=3x-9
x=10°
so the measure of HGI is 21°
4(x+7)=8x-20
4x+28=8x-20
28=4x-20
48=4x
x=12
The x and y coordinates of point S are increased by three to get to the midpoint.
(2,1) ----> (5,4)
To get to point t increase the coordinates by three again.
(5,4) -----> (8,7)
answer: (8,7)
