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3 years ago

What Structure keeps harmful chemicals out of the animal cells

2 answers:

5 0

The cell membrane is what keeps harmful chemicas out of an animal cell. It regulates traffic of all chemicas and proteins in and out of the cell.

dusya [7]3 years ago

4 0

The cell membrane keeps harmful chemicals out of animal cells.

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Write the balanced nuclear equation for the alpha decay of each isotope.

brilliants [131]

Explanation:

First, a quick revision of radioactive decay:

During alpha decay, an alpha particle is emitted from the nucleus —- it is the equivalent of a helium atom (i.e. it has a mass of 4 and an atomic number of 2). So, let's take the following question:

Polonium-210 is a radioisotope that decays by alpha-emission. Write a balanced nuclear equation for the alpha decay of polonium-210.

In symbols, the equation becomes

210/84Po--->?+4/2HE

The sums of the superscripts and of the subscripts must be the same on each side of the equation.

Take 4 away from the mass number (210-4 = 206)

Take 2 away from the atomic number (84-2 = 82). Lead is element number 82.

So, the equation is

210/84 Po--->206/82Pb+4/2He

Now let's try one for beta decay — remember that, in beta decay, a neutron turns into a proton and emits an electron from the nucleus (we call this a beta particle)

Write a balanced nuclear equation for the beta decay of cerium-144)

In nuclear equations, we write an electron as 0^-1e.

144/58Ce-->144/59Pr+^0-1e

Here's a fission reaction.

A nucleus of uranium-235 absorbs a neutron and splits in a chain reaction to form lanthanum-145, another product, and three neutrons. What is the other product?

We write a neutron as 1/0n, so the equation is

235/92U +1/0n--->145/57La+X+3 1/0n

Sum of superscripts on left = 236. Sum of superscripts on right = 148. So X

must have mass number = 236 – 148 = 88.

Sum of subscripts on left = 92. Sum of subscripts on right = 57. So X

must have atomic number = 92 – 57 = 35. Element 35 is bromine.

The nuclear equation is

235/92U+1/0n--->145/57La+88/35Br+31/0N

8 0

3 years ago

Choose the correct answer.

ahrayia [7]

Explanation:

Covalent compounds (solid, liquid, solution) do not conduct electricity. Metal elements and carbon (graphite) are conductors of electricity but non-metal elements are insulators of electricity. Ionic bonds are the electrostatic attraction between positive and negative ions.

Hope its useful... :-)

Brainliest plz

4 0

3 years ago

What is the local, day-by-day changes in the atmoshpheres condition called? A. climate B. weather C. temperature D. precipitatio

zvonat [6]

Answer:

Explanation:

Weather changes daily and varies in different areas around the world

3 0

3 years ago

H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).

timofeeve [1]

Answer:

$K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}$

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

an equilibrium constant is, first of all, a fraction;
in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
each concentration should be raised to the power of the coefficient in the balanced chemical equation;
only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

$K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}$

4 0

4 years ago

Please HELP!

abruzzese [7]

This would be difficult to specify for you because you did not provide the genotype of the other parent. However, there are limitations to the possible combinations, so I will do each to help you out.

1st possibility:

B B

B BB BB

b Bb Bb

Brown eyes: 4 out of 4 or 100%

Blue eyes: 0 out of 4 or 0%.

2nd possibility:

B b

B BB Bb

b Bb bb

Brown eyes: 3 out of 4 or 75%

Blue eyes: 1 out of 4 or 25%.

3rd possibility:

b b

B Bb Bb

b bb bb

Brown eyes: 2 out of 4 or 50%

Blue eyes: 2 out of 4 or 50%.

As long as there is a capital letter in the genotype, the dominant trait will come out. So if the combination is Bb or BB, then BROWN in this case will come out. The only time BLUE eyes will come out is if has two recessives in its genotype or bb.

8 0

4 years ago