The number of significant figures within a number are the amount digits that are required to specify a number to a certain degree of accuracy. In the number, 0.0645 g, the 6 is the most significant figure and 4 is the second most significant figure. Therefore, rounding to two significant figures yields 0.064g.
Answer:
22
Explanation:
when a cell goes through mitosis, it duplicates the amount of its subcellular structures, so it will create 2 more clones. So before it was 20, but one goes through mitosis and preduces two more daughter cells, meaning 22.
Answer:
2487.51.
Explanation:
As per Boyle's law temperature remaining constant the volume of an ideal gas is inversely proportional to its pressure.
pV= k
therefore, p1V1 = p2V2
here V1 = 25.3, p2 = 8.04mm Hg
pressure p1 = 790.5 mm Hg
this means that
25.3×790.5 = 8.04V2
⇒V2= 2487.51
Hence, the required volume is, 2487.51.
Answer:125ml - volume of phosphoic acid
Explanation:
The equation of the reaction is
H3PO4 + 3 NaOH ---> Na3PO4 + 3H2O
Such that I mole of H3PO4 reacts with 3 moles of NaOH to produce the products above.
Given that
M1= Molarity of phosphoric acid = 7.48x10^-2 M
n1= number of moles of phosphoric acid = 1
V1=? ml
M2= Molarity of Sodium hydroxide =0.244 M
V2= volume of sodium hydroxide= 115ml
n2=number of moles of sodium hydroxide = 3
Using the Dilution equation formulae,
M1V1/n1 = M2V2/n2
7.48X10-2 x V1 /1= 0.244M x 115ml/3
V1=0.244Mx115mlx1/0.0748M X 3
V1= 28.06/0.2244= 125.04ml
V1=125.04ml rounded up to 125ml
The gas, 2 mol of H2, occupies the highest volume at STP since at STP the volume of this gas is approximately 44.8 mol as compared to other options this has the greatest amount.
