Calculate how many grams of BeCl2 are required to produce 0.52 grams of MnCl2
1 answer:
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Answer:
600 mg
Explanation:
The initial amount of the drug = 200 mg
The half-life of the drug = 8 hrs
It means that:-
After 6 hours, the concentration becomes :- mg
After 12 hours, the concentration becomes :- mg
After 18 hours, the concentration becomes :- mg
And so on...
Thus,
After infinite time =
Thus,
After infinite time =
The sum of the infinite series is:- =
So,
<u>After infinite time = mg = 600 mg</u>
<u>Answer:</u> The final temperature of water is 32.3°C
<u>Explanation:</u>
When two solutions are mixed, the amount of heat released by solution 1 (liquid water) will be equal to the amount of heat absorbed by solution 2 (liquid water)
The equation used to calculate heat released or absorbed follows:
......(1)
where,
q = heat absorbed or released
= mass of solution 1 (liquid water) = 50.0 g
= mass of solution 2 (liquid water) = 29.0 g
= final temperature = ?
= initial temperature of solution 1 = 25°C = [273 + 25] = 298 K
= initial temperature of solution 2 = 45°C = [273 + 45] = 318 K
c = specific heat of water= 4.18 J/g.K
Putting values in equation 1, we get:
Converting this into degree Celsius, we use the conversion factor:
Hence, the final temperature of water is 32.3°C