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irinina [24]
3 years ago
11

What is the minimum number of clients the travel agent should survey? Note that z=1.96 for a 95% confidence interval.

Mathematics
1 answer:
slega [8]3 years ago
4 0

Answer:

121

Step-by-step explanation:

Given data as per the question

Standard deviation = \sigma = 840

Margin of error = E = 150

Confidence level = c = 95%

For 95% confidence, z = 1.96

based on the above information, the minimum number of clients surveyed by the travel agent is

n = (\frac{z\times \sigma}{E})^2

=  (\frac{1.96\times 840}{150})^2

= 120.47

= 121

hence, the 121 number of clients to be surveyed

Therefore we applied the above formula to determine the minimum number of clients

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Answer:

3

Step-by-step explanation:

first term a= 2

last term tn= 32

common ratio r= -2

number of terms

= tn=ar^n-1

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divide both sides by 2

32/2 = 2*(-2)^n-1/2

16 = (-2)^n-1

Then...use 16 in the power of 2

(-2)^4 = (-2)^n-1

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2 years ago
2. Company A packages roofing nails in boxes that are normally distributed with a mean of 276 nails and a standard deviation of
Natali5045456 [20]

Answer:

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Step-by-step explanation:

We would use z score formula

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x = raw score

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let x = 260 with the mean μ1 = 276 and standard deviation σ = 5.8

let x = 260 with the mean μ2 = 252 and standard deviation σ = 3.4

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Comparing the two z scores, we can see that company B has the probability of producing 260 nails because it has a z score of 2.35 compared to company A with a z score of -2.76.

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How much p² – q² + 2pq is less than -2p² -2q² + 7pq +10 ?
ValentinkaMS [17]

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<u>Step-by-step explanation:</u>

p² - q² + 2pq < -2p² - 2q² + 7pq + 10

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