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nirvana33 [79]
2 years ago
8

a solution must be at a higher temperature than a pure solvent to boil. what colligative property can be employed to achieve thi

s?
Chemistry
2 answers:
Kazeer [188]2 years ago
6 0

Boiling-point elavation.

zimovet [89]2 years ago
5 0

Answer : The colligative property employed to achieve this can be, Elevation in boiling point.

Explanation :

Elevation in boiling point : It is defined as the temperature or boiling point of a liquid (a solvent) will be higher when the another compound is added. This means that a solution must be at a higher temperature or boiling point than a pure solvent.

For example : When a non-volatile solute (a salt) is added to a pure solvent such as water.

The formula for elevation in boiling point will be,

\Delta T_b=k_b\times m

or,

T_b-T^o_b=\frac{1000\times k_b\times w_2}{w_1\times M_2}

where,

T_b = boiling point of solution

T^o_b = boiling point of pure solvent

k_b = boiling point constant

m = molality

w_2 = mass of solute

w_1 = mass of solvent

M_2 = molar mass of solute

Hence, the colligative property employed to achieve this can be, Elevation in boiling point.

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Provide an explanation that is grounded in polarity that better explains why oil is not miscible in vinegar.
butalik [34]

Explanation:

Vinegar is a sour liquid made up of acetic acid compounds. Oil is a complex non-polar chemical compound with a high amount of hydrogen and carbon in its structure.

  • Vinegar is a polar acid, although a weak one.
  • Generally, for a substance to mix with another one, they must be similar.
  • Solubility of compounds controls miscibility.
  • When two substances are miscible, they can be said to be soluble in one another.
  • In solubility, like substances dissolves like substances.
  • This implies that polar compounds will only dissolve polar compounds.
  • Non-polar compounds will only dissolve in non-polar solvents.
  • Since vinegar is polar and oil is non-polar, they will not dissolve one another.

Learn more:

Polarity brainly.com/question/2615067

#learnwithBrainly

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2 years ago
5) Which of these are intensive properties?
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Answer:

For number 5 it is the 2nd one some stants has a mass of 1.25 g And the 2nd 1 number 6It is the 1st 1A subject has a melting point of 40

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Why is a lot of energy needed to break covalent bonds
gulaghasi [49]

Answer:

The strength of a bond between two atoms increases as the number of electron pairs in the bond increases.

Explanation:

6 0
2 years ago
A chemistry student is given the task of analyzing the three unknown samples in the previous question. Compare the densities fro
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It’s B

Explanation:

6 0
2 years ago
s) Suppose we now collect hydrogen gas, H2(g), over water at 21◦C in a vessel with total pressure of 743 Torr. If the hydrogen g
Elenna [48]

This is an incomplete question, here is a complete question.

Suppose we now collect hydrogen gas, H₂(g), over water at 21°C in a vessel with total pressure of 743 Torr. If the hydrogen gas is produced by the reaction of aluminum with hydrochloric acid:

2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)

what volume of hydrogen gas will be collected if 1.35 g Al(s) reacts with excess HCl(aq)? Express  your answer in liters.

Answer : The volume of hydrogen gas that will be collected is 1.85 L

Explanation :

First we have to calculate the number of moles of aluminium.

Given mass of aluminium = 1.35 g

Molar mass of aluminium = 27 g/mol

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Moles of aluminium}=\frac{1.35g}{27g/mol}=0.05mol

The given chemical reaction is:

2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)

As, hydrochloric acid is present in excess. So, it is considered as an excess reagent.

Thus, aluminium is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of hydrogen gas

So, 0.005 moles of aluminium will produce = \frac{3}{2}\times 0.05=0.0750mol of hydrogen gas

Now we have to calculate the mass of helium gas by using ideal gas equation.

PV = nRT

where,

P = Pressure of hydrogen gas = 743 Torr

V = Volume of the helium gas = ?

n = number of moles of hydrogen gas = 0.075 mol

R = Gas constant = 62.364\text{ L Torr }mol^{-1}K^{-1}

T = Temperature of hydrogen gas = 21^oC=[21+273]K=294K

Now put all the given values in above equation, we get:

743Torr\times V=0.075mol\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 294K\\\\V=1.85L

Hence, the volume of hydrogen gas that will be collected is 1.85 L

8 0
3 years ago
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