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dexar [7]
3 years ago
15

BRAINLIEST!!

Chemistry
1 answer:
Juliette [100K]3 years ago
3 0

Answer:

Cesium

Explanation:

cuz i looked at the chart from highest to lowest

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Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°
miskamm [114]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1835 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)    \Delta H_1=157kJ   ( × 4)

(2) P_4(g)+6Cl_2(g)\rightarrow 4PCl_3(g)     \Delta H_2=-1207kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[4\times (-\Delta H_1)]+[1\times \Delta H_2]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-157))+(1\times (-1207))=-1835kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1835 kJ.

6 0
3 years ago
Which of these changes do not involve forming or breaking chemical bonds?
gregori [183]
D
Boiling and melting are both physical changes so do not involve the formation or breakage of chemical bonds.
5 0
3 years ago
Read 2 more answers
At 400 K, the rate of decomposition of a gaseous compound initially at a pressure of 12.6 kPa, was 9.71 Pa s-1 when 10.0 per cen
Neporo4naja [7]

Answer:

The order of the reaction with respect to the gas = 2

Explanation:

Let the original gas pressure be [G₀]

Initial rate of reaction is given as

r = k [G₀]ⁿ

When 10% had reacted, amount of gas left = [0.9G₀], r = 9.71 Pa/s

r = k [0.9G₀]ⁿ = 9.71 (eqn 1)

when 20% had reacted, amount of gas left = [0.8G₀], r = 7.67 Pa/s

r = k [0.8G₀]ⁿ = 7.67 (eqn 2)

Dividing (eqn 1) by (eqn 2)

(9.71/7.67) = [0.9/0.8]ⁿ

1.266 = 1.125ⁿ

1.125ⁿ = 1.266

Take natural logarithms of both sides

n (In 1.125) = In 1.266

n = 0.236/0.118

n = 2.

7 0
3 years ago
Please answer step by step.
Digiron [165]

3 moles of NaOH reacts with 1 mole of phosphoric acid.

<h3>What is the moles ratio of the NaOH and Phosphoric acid reaction?</h3>

The moles ratio of the reaction between NaOH and Phosphoric acid is given by the equation of the reaction below:

3\:NaOH + H_{3}PO_{4} \rightarrow Na_{3}PO_{4} + 3\:H_{2}O \\

Based on the equation of the reaction, 3 moles of NaOH reacts with 1 mole of phosphoric acid.

Learn more about mole ratio at: brainly.com/question/19099163

#SPJ1

3 0
2 years ago
Current flowing in a circuit depends on two variables identify these variables and their relationship to current
Alexxandr [17]
As the electrons are pushed more by the battery, they move faster through the circuit
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