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Mrac [35]
4 years ago
6

Which fact below is describing a base?

Chemistry
1 answer:
QveST [7]4 years ago
6 0
7<span> to 49 10 to 100. 30 Secs. 3. What is the </span>pH<span> value of pure </span>water<span>? 0 3 </span>7<span> 10 ... How do acids </span>taste<span>? </span>bitter sour<span> sweet salty. 30 Secs. </span>7<span>. How do </span>bases taste<span>? </span>bitter<span> ... 8. Which kind of solution would react with a metal? acidic basic </span>neutral water<span> ... cocoa </span>has<span> a </span>bitter taste<span>. It is most likely which of the following? acid </span><span>base neutral</span>
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How many are molecules ( or formula) in each sample?
andre [41]

Answer:

  • 4.010 \times 10^{25} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}
  • 16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}

<u>Explanation</u>:

<u>Number of molecules for 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}</u>

\text { Firstly molar mass is calculated of } \mathrm{NaHCO}_{3}:

Atomic mass of Na + H + C + 3(O)  = 22.99 + 1.008 + 12.01 + 3 × 16.00 = 84.00 g/mol

\text { Number of molecules of } \mathrm{NaHCO}_{3} \text { in } 55.93 \text { kg are as follows: }

55.93 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} \mathrm{NaHCO}_{3}}{84.00 \mathrm{gm} \mathrm{NaHCO}_{3}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number }\right)

=4.010 \times 10^{26} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}

<u>Number of molecules for for \left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}</u>

\text { Firstly molar mass is calculated of } \mathrm{Na}_{3} \mathrm{PO}_{4}

= Atomic mass of 3(Na) + P + 4(O)

= 3(22.99) + 30.97 + 4(16.00) = 163.94 g/mol

459 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} N a_{3} P O_{4}}{163.94 \mathrm{gm} N a_{3} P O_{4}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number) } / 1 \mathrm{mol}\right.

=16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}

8 0
3 years ago
Q#1 Give a combination of four quantum numbers that could be assigned to an electron occupying a 5p orbital.
Gnesinka [82]

Answer:

For an electron in 5p orbital

5,1,-1,+1/2

For an electron in 6d orbital

6,2,-2,+1/2

Explanation:

The term quantum numbers refers to a set of values that can be used to determine the region in space where it is likely to find an electron. This region in space where there is a high probability of finding an electron is known as an atomic orbital. An atomic orbital is actually a wave function according to the Schrödinger wave equation.

There are four quantum numbers used in describing an atomic orbital: the principal quantum number (n), the orbital angular momentum quantum number also called azimuthal or subsidiary quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms).

For a 5p orbital;

n= 5, l= 1, ml= -1,0,1 ms= +1/2 or -1/2

For 6d orbital;

n= 6, l= 2, ml= -2,-1,0,1,2, ms= +1/2 or -1/2

Since we are requested to use a four quantum number description that can be assigned to an electron in these levels;

For an electron in 5p orbital

5,1,-1,+1/2

For an electron in 6d orbital

6,2,-2,+1/2

3 0
3 years ago
describe why emission spectroscopy is a helpful tool in determining the identity of materials in fields like forensic science
IrinaVladis [17]

Answer:

Emission spectroscopy is a helpful tool in determining the identity of materials in fields like forensic science because it has the ability to identify and characterize the elements in a sample obtained for forensic analysis. It accomplishes this by making the sample go through a medium that can disperse the atoms and ions in the element at specified wavelengths.

Explanation:

Atomic emission spectroscopy is a method used in the laboratory to characterize the elements found in a sample needed for a study when they pass through a flame. Inductively coupled plasma is a type of atomic emission spectroscopy which has the ability to excite the components of an element at specific wavelengths when they undergo electromagnetic radiation.

This method can identify the isotopes, atom, and ions present in a sample. This is useful in forensics as it aids the identification of the elements in the sample.

4 0
3 years ago
QUESTION 57 Select the diamagnetic ion. <br> A. Ni2+ B. Cu2+ C. Sr2+ D. Cr3+​
VMariaS [17]

Answer:

c

Explanation:

5 0
3 years ago
Who wants to talk till 1am? hmu:)
Ulleksa [173]

Answer:

Explanation:

lol hi

3 0
3 years ago
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