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3 years ago

Which fact below is describing a base?

1 answer:

6 0

7 to 49 10 to 100. 30 Secs. 3. What is the pH value of pure water? 0 3 7 10 ... How do acids taste? bitter sour sweet salty. 30 Secs. 7. How do bases taste? bitter ... 8. Which kind of solution would react with a metal? acidic basic neutral water ... cocoa has a bitter taste. It is most likely which of the following? acid base neutral

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What mass of potassium chloride, KCl, is produced when 12.6 g of oxygen, 02, is produced?

blagie [28]

Mass of KCl= 19.57 g

<h3>Further explanation</h3>

Given

12.6 g of Oxygen

Required

mass of KCl

Solution

Reaction

2KClO3 ⇒ 2KCl + 3O2

mol O2 :

= mass : MW

= 12.6 : 32 g/mol

= 0.39375

From the equation, mol KCl :

= 2/3 x mol O2

= 2/3 x 0.39375

=0.2625

Mass KCl :

= mol x MW

= 0.2625 x 74,5513 g/mol

= 19.57 g

4 0

2 years ago

Calculate the volume of a 2.0 molar aqueous solution made from 14 miles of K2S

Vilka [71]

Answer:

volume is 7.0 liters

Explanation:

We are given;

Molarity of the aqueous solution as 2.0 M
Moles of the solute, K₂S as 14 moles

We are required to determine the volume of the solution;

We need to know that;

Molarity = Moles ÷ volume

Therefore;

Volume = Moles ÷ Molarity

Thus;

Volume of the solution = 14 moles ÷ 2.0 M

= 7.0 L

Hence, the volume of the molar solution is 7.0 L

5 0

2 years ago

What volume of a 0.232 M hydrobromic acid solution is required to neutralize 10.8 mL of a 0.162 M potassium hydroxide solution?

Naily [24]

Answer:

156 mL hydrobromic acid

Explanation:

3 0

2 years ago

CdF2(s)⇄Cd2+(aq)+2F−(aq)A saturated aqueous solution of CdF2 is prepared. The equilibrium in the solution is represented above.

kupik [55]

Answer:

The correct answer is option a.

Explanation:

$CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)$

Equilibrium concentration cadmium ions = $[Cd^{2+}]=0.0585 M$

Equilibrium concentration fluoride ions = $[F^{-}]=0.117 M$

Molar solubility is the maximum concentration of salt present in water in ionic form beyond that no more salt will exist in its ionic form and will settle down in bottom of the solution.

The molar solubility of the solid cadmium fluoride = 0.0585 M

$CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)$ ..[1]

$NaF(s)\rightleftharpoons Na^{+}(aq)+F^-(aq)$

Due to addition of sodium fluoride will increase concentration of fluoride in the solution.And due to common ion effect the equilibrium will shift in backward direction in [1], that is precipitation of more cadmium fluoride.

Hence, decrease in solubility will be observed.

8 0

2 years ago

A solution is made by dissolving some salt in a beaker of water. The salt is referred to as the.

9966 [12]

The answer is A. Solute

8 0

3 years ago