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sesenic [268]
3 years ago
14

A rectangle has an area of 14 square centimeters. It's length is five cm greater than its width. Find the dimensions.

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0
//Use algebra to find work out the size

14 = w * l
l = 5 + w
14 = w * (5 + w)
14 = 5w + w^2
0 = w^2 + 5w - 14
0 = (w - 2) (w + 7)
=> w = 2cm (as it cannot be negative)

l = w + 5
l = 7cm

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The length of a rectangular house is two and a half times its width. Solve the problem using x to denote the shorter side of the
denpristay [2]

a.  The construct the expression for the area of the rectangle in terms of x is y=2.5x

b. The area should be 2,560.

Given that,

  • the length of a rectangular house is two and a half times its width.

Based on the above information, the calculation is as follows:

a) The expression should be y = 2.5x

b) The area should be

=2.5x^2\\\\= 2.5(32)^2  

= 2560

Learn more: brainly.com/question/1301963?referrer=searchResults

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2 years ago
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The difference between the measures of complementary angles is 24. Find the measure of the smaller angle.
Elena-2011 [213]
X+x-24=180
2x-24=180
2x=204
x=102
x-24=the smaller angle
102-24=the smaller angle
78=the smaller angle

Hope this helps :)
5 0
4 years ago
At the movie theatre, you pay a different price depending on your age. Children 5 and under get in for free. Children ages 6 to
Annette [7]

           {  0          x ≤ 5
f(x) =  {  5           6 ≤ x < 18
           {  8          x ≥ 18

The brackets should be one big bracket.
6 0
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Find the value of x for which ABCD must be a parallelogram
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13x-5=-2x+7
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4 0
3 years ago
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A researcher is wondering whether the smoking habits of young adults (18-25 years of age) in a certain city in the U.S. are diff
kvasek [131]

Answer:

The proportion of young adults (18-25 years of age) in a certain city in the U.S. are not different from the proportion of the general population of young adults in the U.S.

Step-by-step explanation:

The hypothesis for the test can be defined as:

<em>H</em>₀: The proportion of young adults (18-25 years of age) in a certain city in the U.S. are not different from the actual proportion, i.e. <em>P</em> = <em>p</em><em>.</em>

<em>Hₐ</em>: The proportion of young adults (18-25 years of age) in a certain city in the U.S. are different from the actual proportion, i.e. <em>P</em> ≠ <em>p</em><em>.</em>

The test statistic is defined as:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}

Assume that the significance level of the test is, <em>α</em> = 0.05.

The decision rule is:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected. And vice-versa.

It is provided that the <em>p</em>-value of the test is, <em>p</em>-<em>value</em> = 0.076.

The <em>p-</em>value = 0.076 > <em>α</em> = 0.05.

Thus, the null hypothesis will not be rejected at 5% level of significance.

<u>Conclusion</u>:

The proportion of young adults (18-25 years of age) in a certain city in the U.S. are not different from the proportion of the general population of young adults in the U.S.

4 0
4 years ago
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