Answer:
![d = 15h](https://tex.z-dn.net/?f=d%20%3D%2015h)
Step-by-step explanation:
Given
![Charges\ \alpha\ Time](https://tex.z-dn.net/?f=Charges%5C%20%5Calpha%5C%20Time)
Represent charges with d and time with h
So:
when ![t = 2.50\ hours](https://tex.z-dn.net/?f=t%20%3D%202.50%5C%20hours)
Required
Determine the formula
![Charges\ \alpha\ Time](https://tex.z-dn.net/?f=Charges%5C%20%5Calpha%5C%20Time)
In other words,
![d\ \alpha\ h](https://tex.z-dn.net/?f=d%5C%20%5Calpha%5C%20h)
Convert to an equation
![d = k * h](https://tex.z-dn.net/?f=d%20%3D%20k%20%2A%20h)
Where
k = constant of proportion
Substitute values for Charges and Time
![37.50 = k * 2.5](https://tex.z-dn.net/?f=37.50%20%3D%20k%20%2A%202.5)
Solve for k
![k = 37.50/2.50](https://tex.z-dn.net/?f=k%20%3D%2037.50%2F2.50)
![k = 15](https://tex.z-dn.net/?f=k%20%3D%2015)
Substitute 15 for k in ![d = k * h](https://tex.z-dn.net/?f=d%20%3D%20k%20%2A%20h)
![d = 15 * h](https://tex.z-dn.net/?f=d%20%3D%2015%20%2A%20h)
![d = 15h](https://tex.z-dn.net/?f=d%20%3D%2015h)
<em>The above formula models the situation</em>
Answer:
its b
Step-by-step explanation:
(9,-2)
Answer:
a. 5% of the employees will experience lost-time accidents in both years
b. 24% of the employees will suffer at least one lost-time accident over the two-year period
Step-by-step explanation:
a. What percentage of the employees will experience lost-time accidents in both years?
20% last year, of those who suffered last year, 25% during this year. So
![p = 0.2*0.25 = 0.05](https://tex.z-dn.net/?f=p%20%3D%200.2%2A0.25%20%3D%200.05)
5% of the employees will experience lost-time accidents in both years.
b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?
5% during the two years.
10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.
So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.
First year yes, not on the second.
75% of 20%. So, total:
![0.05 + 0.05*0.8 + 0.75*0.2 = 0.24](https://tex.z-dn.net/?f=0.05%20%2B%200.05%2A0.8%20%2B%200.75%2A0.2%20%3D%200.24)
24% of the employees will suffer at least one lost-time accident over the two-year period
The 15-year old age group has the lower ratio (15years = 7:10. 16yr = 10:19
Answer:
(4, 2.5)
Step-by-step explanation: