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igomit [66]
3 years ago
7

Both protons and neutrons are located inside the nucleus of an atom. Changing the number of neutrons in the nucleus would form d

ifferent isotopes of the same element. Which of these BEST describes the outcome of decreasing the number of protons in the nucleus?
Chemistry
1 answer:
skelet666 [1.2K]3 years ago
6 0
By changing the number of protons in an element, you are fundamentally changing it to a different element.

It’s worth remembering that:

Protons identify the element

Electrons determine properties and behavior of the element

Neutrons contribute to isotopes and just help keep everything stable, by separating the charges. Remember opposites attract. Like charges repel.
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How to do q solution, qrxn, moles of Mg , and delta Hrxn?
Helga [31]

Answer:

<em> 14, 508J/K</em>

ΔHrxn =q/n

where q = heat absorbed and n = moles

Explanation:

<em>m = mass of substance (g) = 0.1184g</em>

1 mole of Mg - 24g

<em>n</em> moles - 0.1184g

<em>n = 0.0049 moles.</em>

Also, q = m × c × ΔT

<em> Heat Capacity, C of MgCl2 = 71.09 J/(mol K)</em>

<em>∴ specific heat c of MgCL2 = 71.09/0.0049 (from the formula c = C/n)</em>

<em>= 14, 508 J/K/kg</em>

ΔT=  (final - initial) temp = 38.3 - 27.2

= 11.1 °C.

mass of MgCl2 = 95.211 × 0.1184 = 11.27

⇒ q = 11.27g × 11.1 °C × <em>14, 508 j/K/kg </em>

<em>= 1,7117.7472 J °C-1 g-1</em>

<em />

<em>∴ ΔHrxn = q/n</em>

<em>=1,7117.7472  ÷ 0.1184 </em>

<em>= 14, 508J/K</em>

6 0
4 years ago
Consider a situation in which the enzyme is operating at optimum temperature and pH, and has been saturated with substrate. What
tekilochka [14]

Answer:Increase the enzyme concentration

Explanation:

If the enzyme is saturated, it simply means that all the enzyme molecules present has been bound to substrates.

Of course, there will still be more substrates left in the system since the enzyme is saturated. The reaction rate can now be increased by increasing the enzyme concentration so that more enzyme molecules can be bound to substrates.

4 0
3 years ago
In the following reaction, which component acts as an oxidizing agent? 10 I− (aq) + 2 MnO4− (aq) + 16 H+ (aq) → 5 I2 (s) + 2 Mn2
antiseptic1488 [7]

Answer:

The oxidizing agent is the MnO₄⁻

Explanation:

This is the redox reaction:

10 I⁻ (aq) + 2 MnO₄⁻ (aq) + 16 H⁺ (aq) → 5 I₂ (s) + 2 Mn²⁺ (aq) + 8 H2O (l)

Let's determine the oxidation and the reduction.

I⁻ acts with -1 in oxidation state and changes to 0, at I₂.

All elements in ground state has 0 as oxidation state.

As the oxidation state has increased, this is the oxidation, so the iodide is the reducing agent.

In the permanganate (MnO₄⁻), Mn acts with +7 in oxidation state and decreased to Mn²⁺. As the oxidation state is lower, we talk about the reduction. Therefore, the permanganate is the oxidizing agent because it oxidizes iodide to iodine

3 0
3 years ago
Which statements are true regarding redox reactions? (Note that in redox reactions, the molecule that "causes" another to gain o
Dvinal [7]

Answer:A, C, D, E, F

Explanation:

A. True: Oxidizing agents are electron acceptors. They accept electrons and the get reduced. This means their oxidation number reduces

B. False: Reducing agents do not accept H+ ions. Reducing agents remove oxygen from another substance or give hydrogen to it.

C. True: oxidizing agents oxidizes other molecules but they accept electrons and get reduced themselves. If a molecule accepts electrons it has been reduced.

D True: Redox reactions MAY and may not involve the transfer of hydrogen ions depending on the reactants (H+). But redox in terms of acid and base means the donating and receiving of protons(H+)

E. True: A molecule that has gained H atoms is said to be reduced. Oxidizing agents are always the proton acceptor.

F. True: Oxidizing agents May and may not accept H+. In terms of acid and base oxidizing agents accept protons(H+)

4 0
3 years ago
ADD NOTE
Nikitich [7]

Answer:

2.00 M KOH

Explanation:

Divide moles by volume and make sure your volume is in LITERS, not mL.

0.0400 mol KOH / 0.0200 L = 2.00 M KOH

5 0
3 years ago
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