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igomit [66]
3 years ago
7

Both protons and neutrons are located inside the nucleus of an atom. Changing the number of neutrons in the nucleus would form d

ifferent isotopes of the same element. Which of these BEST describes the outcome of decreasing the number of protons in the nucleus?
Chemistry
1 answer:
skelet666 [1.2K]3 years ago
6 0
By changing the number of protons in an element, you are fundamentally changing it to a different element.

It’s worth remembering that:

Protons identify the element

Electrons determine properties and behavior of the element

Neutrons contribute to isotopes and just help keep everything stable, by separating the charges. Remember opposites attract. Like charges repel.
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Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at
kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}

Squaring both sides, we get

(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}

Solve for <em>M</em>₂:

M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}

M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}

= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}

7 0
3 years ago
How many moles of mercury(II) oxide, HgO, are needed to produce 125 g of oxygen, O2? How many moles of mercury is produced?​
iren2701 [21]

Answer: 7.81 mol HgO (How many moles of mercury(II) oxide, HgO, are needed to produce 125 g of oxygen, O2?)

Explanation:

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Explain heat transfer in your own words​
timofeeve [1]

Answer: thermal conductivity

Explanation:

8 0
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Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. what volume of hydrogen chloride
Anna71 [15]
The reaction between methane gas and chlorine gas to form hydrogen chloride and carbon tetrachloride, all in their gaseous form can be expressed through the chemical reaction below.

        CH₄ + 4Cl₂ --> 4HCl + CCl₄

Let us assume that all the involved gases behaves ideally such that each mole of the gas is equal to 22.4 L. 

Through proper dimensional analysis, the volume of the produced hydrogen chloride is calculated,
    V(HCl) = (1.69 mL CH₄)(1 L CH₄/ 1000 mL CH₄)(1 mol CH₄/22.4 L CH₄)(4 mols HCl/1 mol CH₄)(22.4 L HCl/1 mol HCl)(1000 mL/1 L)
    

    V(HCl) = 6.76 mL

<em>ANSWER: 6.76 mL</em>


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ss7ja [257]

Answer:

a new substance was forming

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