Answer : The Bronsted-Lowry theory was not against the Arrhenius theory, rather it was just a modification to the previous theory of acids and bases. Hydroxide ions are considered as bases because they have the tendency to accept hydrogen ions from acids and form water.
An acid was the one which produces hydrogen ions in solution because it reacts with the water molecules by giving a proton to them.
In a nutshell, he described bases as hydrogen acceptor and acids as hydrogen donors.
<u>Answer:</u>
3.67 moles
<u>Step-by-step explanation:</u>
We need to find out the number of
moles present in 350 grams of a compound.
Molar mass of
= 24.305
Molar mass of
= 35.453
So, one mole of
= 24.305 + (35.453 * 2) = 95.211g
1 Mole in 1 molecule of
= 
Therefore, number of moles in 350 grams of compound = 0.0105 * 350
= 3.67 moles
Answer:
See the answer below
Explanation:
<em>The carbon will have to travel in the form of CO2 from the atmosphere to a primary producer (green plant), from there to a primary consumer (herbivorous animal), and finally to a secondary consumer.</em>
The primary producer (a green plant) would fix the carbon in the CO2 to carbohydrate through a process known as photosynthesis. The equation of the process is as shown below:

The carbon, now in the form of carbohydrate, would then be picked up by an animal (a primary consumer) that feeds on the green plant. The carbon would eventually get into a secondary consumer when the secondary consumer feeds on the primary consumer that fed on the green plant.
Answer:
b. Disulfide bond
Explanation:
Covalent linkage or bonding is a type of bond in which electrons are shared between atoms in a compound or molecule. Each atom contributes to the shared electron.
This is the case of disulfide bonding i.e. S-S, in which two thiol groups (-SH) share electrons with one another. The process of oxidation between two cysteine (amino acid) molecules forms this bond. Hence, Disulfide bond is characterized by a covalent linkage.
Answer:
a) S = 0.0152 mol/L
b) S' = 4.734 g/L
Explanation:
S 2S S...............in the equilibrium
- Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]
a) molar solubility:
⇒ Ksp = ( 2S) ² * S = 1.4 E-5
⇒ 4S² * S = 1.4 E-5
⇒ S = ∛ ( 1.4 E-5 / 4 )
⇒ S = 0.0152 mol/L
b) solubility ( S' ) in grams per liter:
∴ Mw Ag2SO4 = 311.799 g/mol
⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )
⇒ S' = 4.734 g/L