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2 years ago

HELP PLSSSS!!!!! How reactive are the Noble Gases? Do they follow the usual trend for nonmetal reactivity?

Chemistry

2 answers:

sattari [20]2 years ago

8 0

Answer:

Normal Acivity

Explanation:

zaharov [31]2 years ago

3 0

Answer:

Noble gases are not reactive at all since they are stable. 2. I dont think so.

Explanation:

Look at the answer

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Suppose a group of volunteers is planning to build a park near a local lake. The lake is known to contain low levels of arsenic

Kisachek [45]

Answer:

A) 10.75 is the concentration of arsenic in the sample in parts per billion .

B) 7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C) It will take 1.37 years to remove all of the arsenic from the lake.

Explanation:

A) Mass of arsenic in lake water sample = 164.5 ng

The ppb is the amount of solute (in micrograms) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

$\text{ppb}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^9$

Both the masses are in grams.

We are given:

Mass of arsenic = 164.5 ng = $164.5\times 10^{-9} g$

$1 ng=10^{-9} g$

Volume of the sample = V = $15.3 cm^3$

Density of the lake water sample ,d= $1.00 g/cm^3$

Mass of sample = M = $d\times V=1.0 g/cm^3\times 15.3 cm^3=15.3 g$

$ppb=\frac{164.5\times 10^{-9} g}{15.3 g}\times 10^9=10.75$

10.75 is the concentration of arsenic in the sample in parts per billion.

Mass of arsenic in $1 cm^3$ of lake water = $\frac{164.5\times 10^{-9} g}{15.3}=1.075\times 10^{-8} g$

Mass of arsenic in $0.710 km^3$ lake water be m.

$1 km^3=10^{15} cm^3$

Mass of arsenic in $0.710\times 10^{15} cm^3$ lake water :

$m=0.710\times 10^{15}\times 1.075\times 10^{-8} g=7,633,660.130 g$

1 g = 0.001 kg

7,633,660.130 g = 7,633,660.130 × 0.001 kg=7,633.660130 kg ≈ 7,633.66 kg

7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

$\frac{2.74}{41.90} days$

Then days required to remove 7,633.66 kg of arsenic from the lake water :

$=7,633.66\times \frac{2.74}{41.90} days=499.19 days$

1 year = 365 days

499.19 days = $\frac{499.19}{365} years = 1.367 years\approx 1.37 years$

It will take 1.37 years to remove all of the arsenic from the lake.

3 0

2 years ago

The illustration depicts the formation of an ionic chemical bond between lithium and fluorine atoms. Why is the resulting compou

valkas [14]

<span>lithium and fluoride ions are arranged in an alternating three-dimensional crystal lattice. It's not possible to really isolate a single Li-F pair in the solid state. The many positive-negative electrical attractions hold the solid together. Ionic compounds are usually solids at room temperature since these electrical attractions are quite strong.</span>

4 0

2 years ago

Methane reacts with oxygen to produce carbon dioxide and water,What are the products? A. methane and water. B. oxygen and carbon

EleoNora [17]

D, carbon dioxide and water. Methane and oxygen PRODUCE carbon dioxide and water in their reaction.

3 0

3 years ago

Read 2 more answers

Fe2O3 + CO --> Fe + CO2

satela [25.4K]

Answer:

The answer to your question is

1.-Fe₂O₃

2.- 280 g

3.- 330 g

Explanation:

Data

mass of CO = 224 g

mass of Fe₂O₃ = 400 g

mass of Fe = ?

mass of CO₂

Balanced chemical reaction

Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂

1.- Calculate the molar mass of Fe₂O₃ and CO

Fe₂O₃ = (56 x 2) + (16 x 3) = 160 g

CO = 12 + 16 = 28 g

2.- Calculate the proportions

theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90

experimental proportion Fe₂O₃ / CO = 400/224 = 1.78

As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.

3.- 160 g of Fe₂O₃ --------------- 2(56) g of Fe

400 g of Fe₂O₃ --------------- x

x = (400 x 112) / 160

x = 280 g of Fe

4.- 160 g of Fe₂O₃ --------------- 3(44) g of CO₂

400 g of Fe₂O₃ -------------- x

x = (400 x 132)/160

x = 330 gr

3 0

2 years ago

Please help me!!!!!!

Norma-Jean [14]

Answer:

17.8ml-15.6ml is 2.2 ml then convert to cm so 2.2cm^3

4 0

2 years ago