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Mariana [72]
3 years ago
12

Key terms: Reset ____________ anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. ____________ tautomers

have an O-H group bonded to a C=C. ____________ are formed from terminal alkynes with the addition of water using BH3 then H2O2. ____________ are constitutional isomers that differ in the location of a double bond and a hydrogen and exist in an equilibrium with each other. ____________ are compounds that contain a carbon-carbon triple bond. ____________ of a terminal alkyne adds BH₂ to the less substituted, terminal carbon. ____________ tautomers have a C=O and an additional C-H bond.
Chemistry
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

Acetylide , Enol ,aldehydes, tautomers, alkynes , Hydroboration, Keto

Explanation:

Reset <u>Acetylide</u>  anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. <u>Enol </u>tautomers have an O-H group bonded to a C=C. <u>aldehydes </u>are formed from terminal alkynes with the addition of water using BH3 then H2O2. <u>tautomers</u> are constitutional isomers that differ in the location of a double bond and a hydrogen and exist in an equilibrium with each other. <u>alkynes</u> are compounds that contain a carbon-carbon triple bond. <u>Hydroboration</u> of a terminal alkyne adds BH₂ to the less substituted, terminal carbon.<u> Keto</u> tautomers have a C=O and an additional C-H bond.

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4 0
3 years ago
A sample contains 0.1895 g of salt per 50 g of seawater. What is its salinity?
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Use the rule of 3 simple
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7 0
3 years ago
The substance water always has a mass ratio of 11% H to 89% O. If 5.00g of a substance containing H and O was decomposed into .2
Gre4nikov [31]

Answer:

                    No the substance is not water.

Explanation:

                   The balance chemical equation for the decomposition of water is as follow;

                                           2 H₂O = 2 H₂ + O₂

Step 1: <u>Calculate moles of H₂O;</u>

               Moles  =  Mass / M.Mass

               Moles  =  5.0 g / 18.01 g/mol

               Moles  =  0.277 moles of H₂O

Step 2: <u>Calculate Moles of O₂ and H₂ produced by 0.277 moles of H₂O:</u>

According to equation,

                        2 moles of H₂O produced  =  1 mole of O₂

So,

                  0.277 moles of H₂O will produce  =  X moles of O₂

Solving for X,

                     X =  0.277 mol × 1 mol / 2 mol

                     X =  0.138 moles of O₂

Also,

According to equation,

                        2 moles of H₂O produced  =  2 mole of H₂

So,

                  0.277 moles of H₂O will produce  =  X moles of H₂

Solving for X,

                     X =  0.277 mol × 2 mol / 2 mol

                     X =  0.227 moles of H₂

Step 3: <u>Calculate Mass of O₂ and H₂ as;</u>

For O₂:

                 Mass  =  Moles × M.Mass

                 Mass  =  0.138 mol × 31.99 g/mol

                 Mass  =  4.44 g of O₂

For H₂:

                 Mass  =  Moles × M.Mass

                 Mass  =  0.227 mol × 2.01 g/mol

                 Mass  =  0.559 g of H₂

Conclusion:

                   From conclusion it is proved that the amount of H₂ produced by decomposition of 5 g of water should be 0.559 g while in statement it is less i.e. 0.290 g.

6 0
3 years ago
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Answer:

hi! I'm pretty sure your answer is solvent!

Explanation:

not 100% sure but I looked it up on google. solvent does the dissolving, solute is what is being dissolved, and a solution is the solvent + the solute. hope this helped!

7 0
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mr_godi [17]

Answer:

b. Disulfide bond

Explanation:

Covalent linkage or bonding is a type of bond in which electrons are shared between atoms in a compound or molecule. Each atom contributes to the shared electron.

This is the case of disulfide bonding i.e. S-S, in which two thiol groups (-SH) share electrons with one another. The process of oxidation between two cysteine (amino acid) molecules forms this bond. Hence, Disulfide bond is characterized by a covalent linkage.

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