The area of the kite can be found as follows;
Area=[area of XWY]+[areaYWZ]
area XWY=1/2*b*h
=1/2*4*3=6 sq units
area YWZ=1/2*b*h
=1/2*4*4=8 sq units
Hence the area of the kite will be:
Area=6+8=14 sq. units
First let us find the slope:
Points (x , y) = (-2 , 1) and (5 , 8)
Slope m = (y₂ - y₁)/(x₂ - x₁) = (8 - 1) / (5 - -2) = 7/(5 + 2) = 7/7 = 1
Slope m = 1.
Equation of a line by point slope form y - y₁ = m(x - x₁)
Using the point (5, 8) x₁ = 5, y₁ = 8, m = 1
y - y₁ = m(x - x₁)
y - 8 = 1(x - 5)
y - 8 = 1*(x - 5) Point slope form of equation
But let's just simplify further
y = x - 5 +8
y = x + 3
<span>Equation is also y = x + 3
</span>Hope this helps.
<span>expressions for the mean and standard deviation of y if this variable is determined by the expression y
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So basically your gonna regaurd 63.5 as 60 +3.5, 60 is 5*12 and the remaining 3.5 is less than the divisor 5, so it would be the remainder
anwser is 63.5/5 treat as 60/5+3.5/5
so anwser is 60/5+3.5/5=0.7=12.7