Answer:a^2+2ab+b^2
Step-by-step explanation:
First write it out in extended form, (a+b)(a+b) then multiply each term by the other in each parenthesis, such as a*a+b*b+a*b+a*b
Then, once you have done that, simplify it. you will then get the answer a^2+2ab+b^2
9514 1404 393
Answer:
12
Step-by-step explanation:
The length of the hypotenuse, PQ, can be found from the Pythagorean theorem:
PQ² = QR² +PR²
PQ² = 3² + 4² = 25
PQ = √25 = 5
The perimeter is the sum of side lengths:
P = 3 + 4 + 5 = 12
The perimeter of this triangle is 12 units.
Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
Volume of a cone = π r² h/3
I envisioned a cone inside a cube. I only identified the necessary value to compute for the exact volume of the largest cone.
Edges of the cube is 10 inches. When the circle part of the cone is placed in the circle, the diameter would be 10 inches also. I divided it by 2 to get the value of the radius, resulting to 5 inches.
The height of the cone is also the height of the cube. Thus, it is 10 inches.
Volume of the cone = 3.14 * (5in)² * 10in/3
V = 3.14 * 25in² * 3.33 in
V = 261.405 in³ or 261.41 in³ VOLUME OF THE LARGEST CONE THAT CAN FIT IN A 10 INCH CUBE