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4 years ago

24 ÷ [ 33- (1+2)^2] = ?

Mathematics

1 answer:

qaws [65]4 years ago

4 0

Answer:

Below in bold.

Step-by-step explanation:

24 ÷ [ 33- (1+2)^2]

= 24 / ( 33 - 3^2)

= 24 / 24 = 1.

21 + 3 (2-2^2)

= 21 + 3(2 - 4)

= 21 + 3 * -2

= 21 - 6

= 15.

[(14+√4)÷2^3] - 14

= [ (14 + 2) / 8] - 14

= 16/8 - 14

= 2 - 14

= -12.

20 + [18÷(4+1)] - (3^2 + 2)

= 20 + [18÷ 5] - (9 + 2)

= 20 + 3.6 - 11

= 23.6 - 11

= 12.6.

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