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olga_2 [115]
3 years ago
5

50 POINTS!! PLEASE HELP ASAP

Mathematics
2 answers:
sveticcg [70]3 years ago
7 0

Which is the most accurate description of Miko’s work?

After completing the fraction division 5 divided by 5/3, Miko used the multiplication shown to check her work. 3 x 5/3=3/1 x 5/3 = 15/3 or 5

Answer: D) Miko found an incorrect quotient and checked her work using multiplication incorrectly.

I hope this helps you! ☺

natita [175]3 years ago
5 0

Answer:

D. Miko found an incorrect quotient and checked her work using multiplication incorrectly

Step-by-step explanation:

We are given the equation

\frac{5}{\frac{5}{3} }

This can be rewritten as

5*\frac{3}{5} =3

Miko's work is incorrect as she did not multiply by the reciprocal of denominator's fraction. Instead she just multiplied by that fractions.

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A manufacturer of metal fasteners expects to ship an average of 1197.00 boxes of fasteners per day. A random sample of 24 days p
lana66690 [7]

Answer:

The p-value obtained is less than the significance level at which the test was performed, hence, we reject the null hypothesis, accept the alternative hypothesis & conclude that there is evidence showing that the average number of boxes shipped per day is different from 1197.00

Step-by-step explanation:

For hypothesis testing, we first clearly state our null and alternative hypothesis.

The null hypothesis is that there is no evidence showing that the average number of boxes shipped per day is different from 1197.00. That is, there is no significant difference between the number of boxes shipped per day and 1197.00

And the alternative hypothesis is that there is evidence showing that the average number of boxes shipped per day is different from 1197.00

Mathematically, the null hypothesis is

H₀: μ₀ = 1197.00

The alternative hypothesis is

Hₐ: μ₀ ≠ 1197.00

To do this test, we will use the t-distribution because no information on the population standard deviation is known

So, we compute the t-test statistic

t = (x - μ₀)/σₓ

x = sample mean = 1193.69 boxes per day

μ₀ = standard that we're comparing the sample mean with = 1197.00

σₓ = standard error of the sample mean

= (σ/√n)

where n = Sample size = 24 days

σ = standard deviation of the sample = 3.3166 boxes per day

σₓ = (3.3166/√24) = 0.677

t = (1193.69 - 1197) ÷ 0.677

t = -4.89

checking the tables for the p-value of this t-statistic

Degree of freedom = df = n - 1 = 24 - 1 = 23

Significance level = 0.05

p-value (for t = -4.89, at 0.05 significance level, with a two tailed condition) = 0.000061

The interpretation of p-values is that

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 5% = 0.05

p-value = 0.000061

0.000061 < 0.05

Hence,

p-value < significance level

This means that we reject the null hypothesis, accept the alternative hypothesis & conclude that there is evidence showing that the average number of boxes shipped per day is different from 1197.00

Hope this Helps!!!

6 0
3 years ago
HELP PLEASE ME WITH BOTH OF THESE
bulgar [2K]

0.9  3/4  and 15/3

Hope this helps :D

and what do you mean by BOTH of there?

there is only one question

<h2>From:</h2><h2 /><h2>kenny</h2>
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