2, 6, 18, 54, 162, 486...
Start with the number 2.

And continue with that pattern from there.
The problem above is an example of conditional probability. From the name itself, it gives you a condition that a certain event has already happen, or is sure to happen. In this case, the probability would be 100% or 1. The condition says that the probability is 100% if the packages are more than 3. Since, 4 is considered to be more than 3, then the probability is 100%.
Well
It is in the form of a/b + b/a = (a sqr + b sqr)ab
Substitute
(Sin sqr theta + cos sqr theta) +2 cos theta + 1. 2 + 2cos theta
———————————————————————— = ————————-
Sin theta(1+cos theta). Sin theta (1 + cos theta)
2(1+ cos theta)/sin theta(1 + cos theta). {1 + cos theta cancelled}
2/sin theta. Hope it helps :}
Hey!
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First Equation:
2x + 3 = -7
2x + 3 - 3 = -7 - 3 (Subtract 7 to both sides)
2x = -10
2x/2 = -10/2 (Divide 2 to both sides)
x = -5
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Second Equation:
4.5x - 7 = 20
4.5x + (-7) + 7 = 20 + 7 (Add 7 to both sides)
4.5x = 27
4.5x/4.5 = 27/4.5 (Divide 4.5 to both sides)
x = 6
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Third Equation:
-3x + 7 = 28
-3x + 7 - 7 = 28 - 7 (Subtract 7 to both sides)
-3x/-3 = 21/-3 (Divide -3 to both sides)
x = -7
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Answers:
2x + 3 = -7 → x = -5
4.5x - 7 = 20 → x = 6
-3x + 7 = 28 → x = -7
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Hope This Helped! Good Luck!