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3 years ago

What is step 2 in the problem-solving process?

Mathematics

2 answers:

Blababa [14]3 years ago

8 0

Step 1: Read the problem carefully.

Step 2. Write down the facts and figures.

Step 3. Find a relation between what's given and what must be found.

Step 4. Decide which mathematical operation will produce the desired result.

Step 5. Do the work neatly and label the answer correctly.

Step 6. Check your work.

The answer is C.

s344n2d4d5 [400]3 years ago

6 0

Read the problem.
Write down the facts and figures.
Find a relationship between what is given and what must be found.
Do the work.

You might be interested in

Select all the points that are on the line through LaTeX: (0,5)( 0 , 5 ) and LaTeX: (2,8)( 2 , 8 ). Group of answer choices LaTe

Ivenika [448]

Answer:

The points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

Step-by-step explanation:

The equation of the line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

So, the equation of the line passing through two points (0,5) and ( 2, 8 ) is

$y-5=\frac{8-5}{2-0}(x-0)$

$\Rightarrow y=1.5x+5\cdots(i)$

For the point (4,11), pout x=4 in equation (i), we have

$y=1.5\times4 +5=11$ , which is given y coordinate, hence this point (4,11) lies on the line.

For the point (5,10), pout x=5 in equation (i), we have

$y=1.5\times5 +5=12.5,$ which is not the given y coordinate, hence the point (5,10) doesn't lie on the line.

For the point (6,14), pout x=6 in equation (i), we have

$y=1.5\times6 +5=14$ , which is the given y coordinate, hence the point (6,14) lies on the line.

For the point (30,50), pout x=30 in equation (i), we have

$y=1.5\times30 +5=50$ , which is the given y coordinate, hence the point (30,50) lies on the line.

For the point (40,60), pout x=40 in equation (i), we have

$y=1.5\times40 +5=65$ , which is not the given y coordinate, hence the point (40,60) doesn't lie on the line.

Hence, the points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

4 0

3 years ago

PLEASE HELP! Solve each of the following by using the general quadratic formula.

Archy [21]

Using the quadratic formula, the solutions are:

a) $x = \frac{3 \pm \sqrt{41}}{4}$

b) $x = 1 \pm 2i$

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

$y = ax^2 + bx + c$

The solutions are:

$x_1 = \frac{-b + \sqrt{\Delta}}{2a}$

$x_2 = \frac{-b - \sqrt{\Delta}}{2a}$

In which:

$\Delta = b^2 - 4ac$

Item a:

The coefficients are a = 2, b = -3, c = -4, hence:

$\Delta = (-3)^2 - 4(2)(-4) = 41$

$x_1 = \frac{3 + \sqrt{41}}{4}$

$x_2 = \frac{3 - \sqrt{41}}{4}$

Item b:

The coefficients are a = 1, b = 2, c = 2, hence:

$\Delta = (2)^2 - 4(1)(2) = -4$

$x_1 = \frac{2 + \sqrt{-4}}{2} = 1 + 2i$

$x_2 = \frac{2 - \sqrt{-4}}{2} = 1 - 2i$

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0

2 years ago

1. Data are from a normal distribution and the mean is 20 with a standard deviation of 2. a. What % of observations fall between

tangare [24]

Answer:

$P(18$

And we can find this probability with the normal standard distribution and we got:

$P(-1$

Step-by-step explanation:

Let X the random variable that represent the variable of a population, and for this case we know the distribution for X is given by:

$X \sim N(20,2)$

Where $\mu=20$ and $\sigma=2$

We are interested on this probability

$P(18$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

Using this formula we got:

$P(18$

And we can find this probability with the normal standard distribution and we got:

$P(-1$

7 0

4 years ago

Write the equation of the line that passes through the two points: (-4, 11) and (2,-4)

snow_tiger [21]

Answer:

y= - $\frac{5}{2}$ x+1

Step-by-step explanation:

Utilize the formula of $\frac{y2-y1}{x2-x1}$ to find the distance between two points, or in this case, the equation of the line that passes through two points.

Applying the given points to identify the slope

1. Plug the coordinates into the y and x values. $\frac{-4-11}{2+4}$ =- $\frac{15}{6}$ .

1.5. Simplify; divide both the numerator and the denominator by 3. - $\frac{5}{2}$ .

Applying slope and a point to find the y-intercept of the equation of a line

1. Utilize the formula of y=mx. Though this sounds strange, morph the sign of equality into subtraction.

1.5. Result: y-mx

2. Do this for both points.

First point: (-4,11)

y-mx

11 + $\frac{5}{2}$ (-4)

11 + -10 (11-10)

Plug the result and the slope into y=mx+b to find the slope of the line.

Result: y=- $\frac{5}{2}$ x+1.

Check your answer to confirm that the value of y is true for both points

1. Do the same thing you did with the first point, but use the second point this time.

y-mx

-4 + $\frac{5}{2}$ (2)

-4 + 5

Plug the result and the slope into y=mx+b to find the slope of the line.

Result: y=- $\frac{5}{2}$ x+1. Identical to point one's result.

In conclusion, both of the results are the same. Therefore, the equation of the line must be y=- $\frac{5}{2}$ x+1.

3 0

4 years ago

Write an equation of a function that is not linear

arlik [135]

Y=X^2+3 I hope this help you

6 0

3 years ago