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Gekata [30.6K]
3 years ago
15

What does x equal if 2x+y=47​

Mathematics
1 answer:
mestny [16]3 years ago
3 0

Answer:

x=23.5 + -0.5y

Step-by-step explanation:

Simplifying

2x + y = 47

Solving

2x + y = 47

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1y' to each side of the equation.

2x + y + -1y = 47 + -1y

Combine like terms: y + -1y = 0

2x + 0 = 47 + -1y

2x = 47 + -1y

Divide each side by '2'.

x = 23.5 + -0.5y

Simplifying

x = 23.5 + -0.5y

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30/6 = 5
18/6 = 3
It is six.

<span>I hope to have helped you ! :)</span>
5 0
4 years ago
(3+2i)+(5+7i) equals
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I simplify so is 

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Aldo has been given a list of 3 bands and asked to place a vote. His vote must have the names of his favorite and second favorit
aev [14]

Answer:

6

Step-by-step explanation:

1) A B C

2) B A C

3) C A B

4) A C B

5) B C A

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(I probably understood it incorrectly)

8 0
3 years ago
Which statement about the net is true?
Schach [20]
The net cannot be folded to form a pyramid because the faces that are not a base are not all triangles

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A pyramid can have ANY polygon as its base, as long as all the other rest of the shapes are triangles.

Depending on the base, the number of triangles in a net of a pyramid must match the number of sides its particular base has.

For example, if you have a square pyramid turned into a net:
The base is a square (4 sides)
There should be 4 triangles on each side.

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Hope this helps!
3 0
3 years ago
The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length
Artemon [7]

Answer:

Width = 10 inches

Step-by-step explanation:

Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.

We can establish the following values to help us solve for the width of a rectangle:

Perimeter (P) = 68 inches

Length (L) = 14 + W inches

Width (W) = unknown

<h3 /><h3><u>Solve for the Width (W)</u></h3>

P =  2(L + W)  ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.

Divide both sides by 2:

\displaystyle\mathsf{\frac{P}{2}\:=\:\frac{2(L\:+\:W)}{2}}

\displaystyle\mathsf{\frac{P}{2}\:=L\:+\:W}

Substitute the value of the Perimeter and the length (L) into the formula:

\displaystyle\mathsf{\frac{68}{2}\:=14\:+W\:+\:W}

Combine like terms on the right-hand side, and simplify the left-hand side of the equation:

\displaystyle\mathsf{34\:=14\:+2W}

Subtract 14 from both sides:

34 - 14 = 14 - 14 + 2W

20 = 2W

Divide both sides by 2 to solve for the width (W):

\displaystyle\mathsf{\frac{20}{2}\:=\:\frac{2W}{2}}

W = 10 inches

Therefore, the width of the rectangle is 10 inches.

<h3 /><h3><u>Double-check:</u></h3>

Verify whether the derived value for the width is correct:

P = 2L + 2W

68 = 2(14 + 10) + 2(10)

68 = 2(34) + 20

68 = 48 + 20

68 = 68 (True statement).  

Thus, the length of the rectangle is 34 inches, and the width is 10 inches.

4 0
3 years ago
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