Mr. drove 3 times more then Mrs.. ok
so how far Mrs. drove will be X
and Mr. will be Y
but we know that Mr. drove 3 times more then Mrs therefor
Y= 3X
and the Sum = 3,200
3,200=X+Y
3,200= X+(3X)
3,200=4X
div both by 4
800=X
now we know how far Mrs drove now to find Mr.
again "Mr. drove 3 times more then Mrs"
800 * 3 = 2,400
Answer: 0.02
Step-by-step explanation:
OpenStudy (judygreeneyes):
Hi - If you are working on this kind of problem, you probably know the formula for the probability of a union of two events. Let's call working part time Event A, and let's call working 5 days a week Event B. Let's look at the information we are given. We are told that 14 people work part time, so that is P(A) = 14/100 - 0.14 . We are told that 80 employees work 5 days a week, so P(B) = 80/100 = .80 . We are given the union (there are 92 employees who work either one or the other), which is the union, P(A U B) = 92/100 = .92 .. The question is asking for the probability of someone working both part time and fll time, which is the intersection of events A and B, or P(A and B). If you recall the formula for the probability of the union, it is
P(A U B) = P(A) +P(B) - P(A and B).
The problem has given us each of these pieces except the intersection, so we can solve for it,
If you plug in P(A U B) = 0.92 and P(A) = 0.14, and P(B) = 0.80, you can solve for P(A and B), which will give you the answer.
I hope this helps you.
Credit: https://questioncove.com/updates/5734d282e4b06d54e1496ac8
Answer:
Hope this solution helps you
Answer:

Step-by-step explanation:
Given
See attachment
Required
Determine the slope of the line
From the attachment, we have the following points

and

The slope m is then calculated using:

Substitute values for the x's and y's




<em>Hence, the slope is 0</em>
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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