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weeeeeb [17]
3 years ago
8

Dana is filling a 1.5 gallon watering can at a rate of 0.75 gallon per minute. What is the domain of the function that represent

s the volume of water in the can after x minutes?
Mathematics
1 answer:
Butoxors [25]3 years ago
6 0

Answer:

0 ≤ x ≤ 2

Step-by-step explanation:

A function show the relationship between an independent variable and a dependent variable. The independent variable (input) does not depend on other variables while the dependent variable (output) depend on other variables.

In this question, the volume of the water is the dependent variable and the time taken is the independent variable. Let y represent the volume of the water and x represent the time taken. Therefore:

y = 0.75x

The domain of the function is the set of independent variable, it can be gotten by determining x when y is minimum and maximum. Hence:

For y = 0

0 = 0.75x

x = 0/ 0.75 = 0

For y = 1.5 gallon

1.5 = 0.75x

x = 1.5/0.75 = 2

Hence, the domain = 0 ≤ x ≤ 2

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The total price of a shirt and a cap is $11. If the price of the shirt was doubled and the price of the cap was three times its
Oliga [24]

Answer:

shirt= $8

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Step-by-step explanation:

rearrange one of the equations

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then plug into the other equation

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8 0
4 years ago
I need help with this
Xelga [282]

Somewhere you're given the equation for height as a function of time:

... h(t) = -16t² + v₀·t . . . . . . where v₀ is the initial vertical velocity in ft/s

For v₀ = 224, this becomes

... h(t) = -16t² + 224t

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4 0
3 years ago
Y is directly proportional to x when y=30, x=6
rosijanka [135]

Answer:

a) y = 5x

b) y = 60

Step-by-step explanation:

Since, y is directly proportional to x when y=30, x=6

\therefore \:  y \:  \alpha \:  \: x \\ \therefore \:  y =  kx ...(1) \\ plug \: y = 30 \: and \: x = 6  \: in \: eq \: (1)\\ 30 = k \times 6 \\ k =  \frac{30}{6}  \\ k = 5 \\ plug \: k = 5 \: in \: (1) \\ y = 5x....(2) \: (required \: equation) \\ plug \: x = 12 \: in \: eq \: (2) \\ y = 5 \times 12 \\  \huge \red{ \boxed{y = 60}}

4 0
3 years ago
Can someone help???
AleksandrR [38]

Answer: I Included a picture below.

Hope this helps, if you have any questions please leave a comment. :)

6 0
3 years ago
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