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weeeeeb [17]
3 years ago
8

Dana is filling a 1.5 gallon watering can at a rate of 0.75 gallon per minute. What is the domain of the function that represent

s the volume of water in the can after x minutes?
Mathematics
1 answer:
Butoxors [25]3 years ago
6 0

Answer:

0 ≤ x ≤ 2

Step-by-step explanation:

A function show the relationship between an independent variable and a dependent variable. The independent variable (input) does not depend on other variables while the dependent variable (output) depend on other variables.

In this question, the volume of the water is the dependent variable and the time taken is the independent variable. Let y represent the volume of the water and x represent the time taken. Therefore:

y = 0.75x

The domain of the function is the set of independent variable, it can be gotten by determining x when y is minimum and maximum. Hence:

For y = 0

0 = 0.75x

x = 0/ 0.75 = 0

For y = 1.5 gallon

1.5 = 0.75x

x = 1.5/0.75 = 2

Hence, the domain = 0 ≤ x ≤ 2

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S_A_V [24]

Answer: B. -9/8

Step-by-step explanation:

8 0
3 years ago
Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

BA • BC = 4

Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

4 = (4)(0) + (2)(t) + (0)(1)

4 = 0 + 2t + 0

4 = 2t

2 = t

t = 2

Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

Dot product: a • b = |a| |b| cos(angle)

BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

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1 year ago
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Answer:

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Step-by-step explanation:

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gogolik [260]
I'm not positive I know the answer, but I have a feeling that because it's asking that you select all that apply, there is more than just one answer.

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