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3 years ago

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Michelle is rolling two six-sided dice, numbered one through six. What is the probability that the sum of her rolls is 4? A. B.

C. D.

1 answer:

Bad White [126]3 years ago

5 0

Answer:

<h3>The probability that the sum of Michelle's rolls is 4 is 0.083 </h3><h3>∴ P(A)=0.083 </h3>

Step-by-step explanation:

Given that Michelle is rolling two six-sided dice, numbered one through six.

<h3>To find the probability that the sum of her rolls is 4:</h3>

$s={\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}\}$

<h3>∴ n(s)=36</h3>

Let P(A) be the probability that the sum of her rolls is 4

Then the possible rolls with sums of 4 can be written as

$A={\{(1,3),(2,2),(3,1)}\}$

<h3>n(A)=3</h3>

The probability that the sum of her rolls is 4 is given by

$P(A)=\frac{n(A)}{n(s)}$

$=\frac{3}{36}$

$=\frac{1}{12}$

=0.083

<h3>∴ P(A)=0.083 </h3><h3>∴ the probability that the sum of Michelle's rolls is 4 is 0.083 </h3>

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