Evaluate: 2x + 28 < 100 Your answer I

8n = -3m + 1; n = -2, 2, 4

bogdanovich [222]

I am assuming you want to solve for m in each case

8n = -3m + 1

8(-2) = -3m + 1

-16 = -3m + 1

-3m = -17

m = $\frac{17}{3}$

8(2) = -3m + 1

16 = -3m + 1

-3m = 15

m = -5

8(4) = -3m + 1

32 = -3m + 1

-3m = 31

m = $\frac{31}{3}$

8 0

3 years ago

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Consider the following function :y=1/(x+5)+2 How does the graph of this function compare with the graph of the parent function,

Paraphin [41]

With respect to the parent function,
y = 1/(x+5) +2
is translated 5 units left and 2 units up.

4 0

3 years ago

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1. A trapezoid has an area of 91 m2. The height of the trapezoid is 7 m and the measure of one base is twice the height. What is

Lynna [10]

The area of the trapezoid is given by:
A = (1/2) * (b1 + b2) * (h)
Where,
b1, b2: bases of the trapezoid
h: height
Substituting values we have:
91 = (1/2) * ((2 * 7) + b2) * (7)
Rewriting we have:
91 = (1/2) * (14 + b2) * (7)
(2/7) * 91 = 14 + b2
b2 = (2/7) * 91 - 14
b2 = 12 m
Answer:
The measure of the other base of the trapezoid is:
b2 = 12 m

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3 years ago

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Value of the derivative of g(x)=8-10Cosx at 'x=0' is?

VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Pre-Calculus

Unit Circle

Calculus

Derivatives
Derivative Notation
The derivative of a constant is equal to 0
Derivative Property: $\frac{d}{dx} [cf(x)] = c \cdot f'(x)$
Trig Derivative: $\frac{d}{dx} [cos(x)] = -sin(x)$

Step-by-step explanation:

Step 1: Define

g(x) = 8 - 10cos(x)

x = 0

Step 2: Differentiate

Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
Simplify Derivative: g'(x) = 10sin(x)

Step 3: Evaluate

Substitute in x: g'(0) = 10sin(0)
Evaluate Trig: g'(0) = 10(0)
Multiply: g'(0) = 0

3 0

3 years ago

A grocery store recently changed their apple supplying vendor. The vendor told the store manager that the mean weight for each a

yarga [219]

Answer:

b) 0.0042495

c) 0.048021

Hence, the probability of the mean weight that the 10 apples exceeds 8.2 ounces of this customer wil be higher than the last customer in part b because the number of random samples in part b is greater that that in part c

Step-by-step explanation:

mean of 7.5 ounces and a standard deviation of 1.33 ounce

When random number of samples are given, we solve using z score with the formula

= z = (x-μ)/σ/√n, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

n is the random number of samples

(a) One customer comes to this grocery store and randomly picks 25 apples. What is the mean and standard deviation of the distribution of the mean weight for 25 apples?

(b) What is the probability that the mean weight of 25 apples exceeds 8.2 ounces?

x > 8.2 ounces

= z = (x - μ)/σ/√n

z = (8.2 - 7.5)/1.33/√25

z = (8.2 - 7.5)/1.33/5

z = 2.63158

Probability value from Z-Table:

P(x<8.2) = 0.99575

P(x>8.2) = 1 - P(x<8.2) = 0.0042495

(c) Another customer randomly picks 10 apples. Will the probability of the mean weight that the 10 apples exceeds 8.2 ounces of this customer be higher than the last customer in part b?

For n= 10

x > 8.2 ounces

= z = (x - μ)/σ/√n

z = (8.2 - 7.5)/1.33/√10

z = 1.66436

Probability value from Z-Table:

P(x<8.2) = 0.95198

P(x>8.2) = 1 - P(x<8.2) = 0.048021

Hence, the probability of the mean weight that the 10 apples exceeds 8.2 ounces of this customer wil be higher than the last customer in part b because the number of random samples in part b is greater that that in part c

4 0

3 years ago