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svetoff [14.1K]
3 years ago
7

WILL GIVE BRANLIEST ANSWER ASAP

Mathematics
2 answers:
harina [27]3 years ago
7 0

Answer:

{2, 4}

Step-by-step explanation:

Intersection of given sets would be {2,4}.

polet [3.4K]3 years ago
3 0

Answer:

C) {2,4}

Step-by-step explanation:

C) {2,4}

The union would be all of them.  The intersection are the ones they have in common.

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Solve for x. 4−(2x+4)=5 x=6 x=−52 x=−10 x=32
sashaice [31]

Answer:

Step-by-step explanation:

4−(2x+4)=5

4-2x - 4 =5

-2x = 5

x= -5/2 = -2.5

5 0
3 years ago
NEED HELP PLEASEE
Kruka [31]

Answer:

Simplify−412+16t+48.h=16t−1633

Step-by-step explanation:

4 0
3 years ago
Please help asap!!<br> Answer this using a graphing method please!
Zepler [3.9K]

Answer:

the connection is at 4 on x axis and 5 on y axis, so the solutions are x=4; y=5

3 0
3 years ago
The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


4 0
4 years ago
One number is 20 times another number. The product of the two numbers is 180. Write an equation and use it to find all pairs of
nadezda [96]
Y = 20x

y • x = 180

180/x = y

180/x = 20x

180 = 20x^2

x^2 = 6

x = + or - 3

Therefore y must equal + or - 60.
8 0
3 years ago
Read 2 more answers
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