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3 years ago

Help.. Suppose Q is the midpoint of PR

Mathematics

1 answer:

8090 [49]3 years ago

6 0

Answer:

$3x+41$ or 38

Step-by-step explanation:

If Q is the midpoint of Line PR, then lines PQ and QR add up to equal Line PR. We then get

$PQ=6x+25\\QR=16-3x\\PQ+QR=PR\\6x+25+16-3x=PR\\3x+41=PR\\$

If you want to know the exact number that PR is, we can do additional steps where PQ = QR.

$PQ=6x+25\\QR=16-3x\\PQ=QR\\6x+25=16-3x\\9x+25=16\\9x=-9\\x=-1\\\\3x+41=PR\\3(-1)+41=PR\\-3+41=PR\\38=PR\\PR=38$

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Answer:

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I hope this helps you

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4 years ago

Solve systems of equations for y and x: −5y + 8x = −18 5y + 2x = 58

Natali5045456 [20]

Answer:

(4, 10)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Coefficients
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

-5y + 8x = -18

5y + 2x = 58

Step 2: Solve for x

Elimination

Combine 2 equations: 10x = 40
[Division Property of Equality] Divide 10 on both sides: x = 4

Step 3: Solve for y

Substitute in x [Original equation]: -5y + 8(4) = -18
Multiply: -5y + 32 = -18
[Subtraction Property of Equality] Subtract 32 on both sides: -5y = -50
[Division Property of Equality] Divide -5 on both sides: y = 10

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