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borishaifa [10]
3 years ago
9

5 to the root of five(3 to the root of 6 + the root of 6)

Mathematics
1 answer:
alexdok [17]3 years ago
7 0
5\sqrt{5}(3\sqrt{6} + \sqrt{6})
5\sqrt{5}(4\sqrt{6})
20\sqrt{30}
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What is the relationship between the graphs of f(x) = x^2 and g(x) = x^2 + 6?
Tamiku [17]
They have the same slope, but g(x) intercepts the y axis higher.
6 0
2 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
What is the least common denominator of 1/2 and 9/10
nirvana33 [79]

Answer:the least common denominator is 10 because 5x2 is 10 and then 10x1 is 10 its the least for both of them

Step-by-step explanation:

3 0
1 year ago
If 1 yard = 3 feet and 1 mile = 5,280 feet, how many yards are there in 2 miles?
Mars2501 [29]
2 miles = 3520 yards
FORMULA multiply the length value by 1760
3 0
3 years ago
b is the midpoint of AC and E is the midpoint of BD if A(-9,-4) C(-1,6) and E(-4,-3) find the coirdinates of D
natima [27]

To find the coordinate of the point D, we can use the Midpoint point of a line Segment formula. Calculation of the formula are as follows,

Given two points A(x1,y1) and C(x2,y2), we need to locate the midpoint coordinate of this line denoted as B(x,y).

To solve for the value of x and y, we get,

x=(x1+x2)/2 and y=(y1+y2)/2

For the given problem, we need to solve first the midpoint coordinate of AC which is B.

So, A(-9,-4)=A(x1,y1) and C(-1,6)=C(x2,y2)

Hence,

B(x,y)=B((-9+(-1))/2, (-4+6)/2)=B(-10/2,2/2)=B(-5,1)

Now, since the midpoint is given but one point in the line is missing. To solve for the missing point D(x2,y2), we need to use the Midpoint Segment Formula.

 That is, B(-5,1)=B(x,y) and E(-4,-3)=E(x1,y1)

So,

x=(x1+x2)/2 and y=(y1+y2)/2

-5=(-4+x2)/2 and 1=(-3+y2)/2

By Cross Multiplication and Transposing method,

-5(2)=-4+x2 and 1(2)=-3+y2

x2=-10+4=-6 and y2=3+2=5

Thus, the coordinate of D is D(-6,5).

5 0
4 years ago
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