Answer:
The minimum score required for recruitment is 668.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Top 4%
A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?
Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.
Rounded to the nearest whole number, 668
The minimum score required for recruitment is 668.
the bus goes 65 miles every hour. so: 1hr = 65mi
to find how many miles it goes every 2.5 hours, we multiply each side by 2.5:
2.5hrs = 162.5mi
Step-by-step explanation:
this is clearly not a linear sequence (the terms don't have the same difference).
so, it has to be a geometric sequence.
the common ratio is r.
s2 = s1 × r
16 = 64 × r
r = 16/64 = 1/4
control :
s3 = s2×r
4 = 16 × 1/4 = 4
correct.
Step 1
Given;
Required; To find the difference in interest between the two periods.
Step 2
State the formula for simple interest
Step 3
Find the interest when the rate is 8%
Therefore the interest is given as;
Step 4
Find the interest in 1980 with a 20% rate
The interest is given as;
Step 5
Find the difference in interest between the two rates.
Hence, the difference in interest between the two rates = $11095.89
The account balance after 3 years if the interest is compounded continuously is $5,142.62
<h3>How to find compound interest?</h3>
- Principal, P = $4,700
- Time,t = 3 years
- Interest rate, r = 3%
r = 3/100
r = 0.03 rate per year,
A = Pe^rt
A = 4,700.00(2.71828)^(0.03)(3)
= 12,775.916^0.09
A = $5,142.62
Therefore, the account balance after 3 years if the interest is compounded continuously is $5,142.62
Learn more about compound interest:
brainly.com/question/24924853
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