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3 years ago

I need help I don’t know how to do this

Mathematics

1 answer:

vfiekz [6]3 years ago

4 0

Answer:

Step-by-step explanation: The bigger triangle is 6 times bigger than the smaller one.

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Suppose that $2000 is invested at a rate of 4%, compounded semiannually. Assuming that no withdrawals are made, find the total a

creativ13 [48]

Answer:

Step-by-step explanation:

A = P(1+r/n)^ nt

A = 2000(1+.04/2)^(5*2)

A = $2000(1.02)^{10}$ = $2437.99

5 0

3 years ago

What's the standard equation of the circle with the general equation x2 + y2 + 4x – 2y – 20 = 0? answers: 1) (x + 2)2 + (y – 1)2

gizmo_the_mogwai [7]

Answer:

4). (x + 2)^2 + (y - 1)^2 = 25.

Step-by-step explanation:

x^2 + y^2 + 4x - 2y - 20 = 0

x^2 + 4x + y^2 - 2y = 20

Completing the square on the x and y terms:

(x + 2)^2 - 4 + (y - 1)^2 - 1 = 20

(x + 2)^2 + (y - 1)^2 = 20 + 4 + 1

(x + 2)^2 + (y - 1)^2 = 25.

3 0

3 years ago

The drama club is selling tickets to its play. An adult ticket costs $15 and a student ticket costs $11. The auditorium will sea

spin [16.1K]

Answer:

83 adult tickets and 217 student tickets.

Step-by-step explanation:

Let number of adult tickets sold = $x$

Given that total number of tickets = 300

So, number of student tickets = 300 - $x$

Cost of adult ticket = $15

Cost of student ticket = $11

Total collection from adult tickets = $ $15x$

Total collection from student tickets = $(300-x)\times 11 = 3300-11x$

Given that overall collection = $3630

$15x+(3300-11x) = 3630\\\Rightarrow 15x-11x=3630-3300\\\Rightarrow 4x = 330\\\Rightarrow x = 82.5$

So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.

Now , collection = $3632

4 0

3 years ago

Step by step workout of ;<br> log x^3+log 5x=5 log 2-log 2/5

Charra [1.4K]

Answer:

x = 2

Step-by-step explanation:

$log \: {x}^{3} + log \: 5x = 5log \: 2 - log \: \frac{2}{5} \\ \\ \therefore \: log( {x}^{3} \times 5x) = log {2}^{5} - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log 32 - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(32 \times \frac{5}{2} \bigg) \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(16 \times 5) \\ \\ \therefore \: 5{x}^{4}= 16 \times 5 \\ \\ \therefore \: {x}^{4}= {2}^{4} \\ \\ \huge \purple{ \boxed{\therefore \: {x} = 2}}$

4 0

3 years ago

9th question help ?!

Daniel [21]

Hey there! :)

You have to find the area of all of them and add it together.

Formulas:

Area of a square: l · w
Area of a triangle: (b · h) ÷ 2

Square -

l = 3
w = 3

3 × 3 = 9

Triangle -

b = 3
h = 3

(3 × 3) ÷ 2
9 ÷ 2 = 4.5

There are 4 triangles

4.5 × 4 = 18

9 + 18 = 27

The surface area ⇒ 27 cm²

5 0

4 years ago