<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Answer:
Step-by-step explanation:
Consider the options for this question are as follow,
Here, In triangles ABC and PQR,
AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,
Since,
We know that,
The corresponding sides of similar triangles are in same proportion,
Thus,
Root of ( 20^2 - 16^2 ) = 12
Answer:
h = 76
Step-by-step explanation:
2 + h - 48 = 30
h + 2 - 48 = 30
h - 46 = 30
h - 46 + 46 = 30 + 46
h = 76
You could make this really simple by dividing 300 by 4 to see how much 1/4 of that is and then subtracting 1/4 from 300 to see how much dashawn's water bottle holds.
300/4 =75 so 1/4 is equal to 75 mL
300-75=225mL
Dashawn's water bottle holds 225mL
