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Amanda [17]
4 years ago
7

How do you get the answer to 37+10+14=_-23

Mathematics
1 answer:
Sholpan [36]4 years ago
7 0
By solving algebraically. add all the terms on the left to get 61=x-23 then add 23 to both sides to get 84=x and thats the answer x=84
Good Luck!
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PLEASE ANSWER ASAP LOOK AT THE PICTURE DUE IN 2 SECONDS !!!!!!!!!!!!!!
katrin2010 [14]
Answer: x> 30

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3 0
3 years ago
Read 2 more answers
A fishing boat is hauling up a lobster trap. A machine called a winch pulls the trap up at a constant rate of 85 feet per minute
alexandr402 [8]

Answer:

A, C, D

Step-by-step explanation:

We know that velocity is 85 feet/minute, and distance is velocity * time, so we can multiply 85 by time to see if it equals the output

(A) 1*85-85

(B) 0.85*85 = 72.75

(C) 0.2*85 = 14

(D) 3.5*85 = 297.5

(E) 4* 85 = 340

A, C, and D match up

8 0
3 years ago
Bloomington Nail Salon is having a special this month on services. Over the weekend, they performed 49 manicures and 16 pedicure
marshall27 [118]

Answer: The salon charges $16 for a manicure and $25 for a pedicure.

Step-by-step explanation:

Let x represent the amount charged by the salon for a manicure.

Let y represent the amount charged by the salon for a pedicure.

Over the weekend, they performed 49 manicures and 16 pedicures, bringing in a total of $1,184 in receipts. It means that

49x + 16y = 1184- - - - - - - - - - 1

So far this week, they have administered 31 manicures and 33 pedicures, with receipts totalling $1,321. It means that

31x + 33y = 1321- - - - - - - - - - 2

Multiplying equation 1 by 31 and equation 2 by 49, it becomes

1519x + 496y = 36704

1519x + 1617y = 64729

Subtracting, it becomes

- 1121y = - 28025

y = - 28025/- 1121

y = $25

Substituting y = 25 into equation 1, it becomes

49x + 16 × 25 = 1184

49x + 400 = 1184

49x = 1184 - 400

49x = 784

x = 784/49

x = $16

5 0
4 years ago
Find the coordinates of the point of intersection of all parabolas that have equation y=x2+px +q with p+q=2020. The point of int
ioda

Answer:

(1,2021)

Step-by-step explanation:

P and q can vary subject to their sum being 2020.

Consider one parabola with p1 and q1 and another with p2 and q2.

y1=(x1)^2+(p1)(x1)+(q1)

y1=(x2)^2+(p2)(x2)+(q2)

At their intersection, the x and y coordinates are the same.

y1=y2=y

x1=x2=x

x^2+(p1)x+(q1)=x^2+(p2)x+(q2)

Solve for x

x(p1-p2)=q2-q1

x=(q2-q1)/(p1-p2)

Use the constraint that p+q=2020 to eliminate p1 and p2.

p1=2020-q1

p2=2020-q2

x=(q2-q1)/(2020-q1-2020+q2)

x=(q2-q1)/(q2-q1)

x=1

Substitute in the equation for y.

y=1^2+p(1)+q

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3 0
3 years ago
4 miles out of 166 miles.
mylen [45]

Answer:

166 - 4 = 162

Step-by-step explanation:

Your question mad no sense !!

6 0
3 years ago
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