3 years ago

What is 1 over 2 x + 13 = 9

Mathematics

1 answer:

vekshin13 years ago

6 0

1/2x+13=9

2x1/2x+2x13=2x9

x+26=18

x=18-26

x=-8

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Can someone please help me on this question?

Olin [163]

The ends of the graph will extend in opposite directions.

Hope this helped!

6 0

3 years ago

Dakota and Christine went shopping. Dakota bought two scarves and one hat for $13 Christine bought one scarves and two hats for

White raven [17]

One scarf=s
One hat=h

2s+h=13
s+2h=14

h=13-2s
(plug that into the other equation)

s+2(13-2s)=14
s+26-4s=14
26-3s=14
-3s=-12
s=4

One hat=$5
One scarf=$4
5+4=9
Price of one hat AND one scarf is $9

5 0

3 years ago

Simplly the square root of 75z^18

notsponge [240]

Answer:5√(3)z^9

Step-by-step explanation:

Square root of 75z^18

√(75z^18)

√(75) x √(z^18)

√(25x3) x (z^18)^(1/2)

√(25) x √(3) x z^(18x1/2)

5 x √(3) x z^9

5√(3)z^9

8 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$