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likoan [24]
3 years ago
14

How do i find an equation for a line with an x-intercept of 4 and a y-intercept of -2

Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0

Answer:

The equation of a line is y = ax + b, where a is the slope and b is the y-intercept.  

Since we have the y-intercept, all we need to do is find the slope. To find the slope, you need 2 coordinates.

The y-intercept is where the line crosses the y axis, so it is where x is 0. Since the y intercept is -2, that means the first coordinate is (0, -2)

The x-intercept is where the line crosses the x axis, so it is where y is 0. Since the x intercept is 4, that means the second coordinate is (4, 0)

Since we already have the y-intercept, all we do is put the slope in the equation: y = 1/2x - 2.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The equation of the curve is

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This would give the slope of the tangent line at any given point of which x coordinate is known. In the present case it is  x = \sqrt{\frac{1}{7} }

Then slope would accordingly be

Y'=\frac{7}{\sqrt{1-49/49} }

= ∞

For, x = \sqrt{\frac{1}{7} }, Y = sin^{-1}(7/7)= \pi/2

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3 years ago
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